AtCoder Beginner Contest 126
C
Dice and Coin
AtCoder
⌀ 638
原题
← BD →
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Problem Statement

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Snuke has a fair $N$-sided die that shows the integers from $1$ to $N$ with equal probability and a fair coin. He will play the following game with them:

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  1. Throw the die. The current score is the result of the die.
  2. As long as the score is between $1$ and $K-1$ (inclusive), keep flipping the coin. The score is doubled each time the coin lands heads up, and the score becomes $0$ if the coin lands tails up.
  3. The game ends when the score becomes $0$ or becomes $K$ or above. Snuke wins if the score is $K$ or above, and loses if the score is $0$.
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You are given $N$ and $K$. Find the probability that Snuke wins the game.

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Constraints

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  • $1 ≤ N ≤ 10^5$
  • $1 ≤ K ≤ 10^5$
  • All values in input are integers.
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Input

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Input is given from Standard Input in the following format:

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N K

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Output

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Print the probability that Snuke wins the game. The output is considered correct when the absolute or relative error is at most $10^{-9}$.

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样例

Input #1
3 10
Output #1
0.145833333333
- If the die shows $1$, Snuke needs to get four consecutive heads from four coin flips to obtain a score of $10$ or above. The probability of this happening is $\frac{1}{3} \times (\frac{1}{2})^4 = \frac{1}{48}$. - If the die shows $2$, Snuke needs to get three consecutive heads from three coin flips to obtain a score of $10$ or above. The probability of this happening is $\frac{1}{3} \times (\frac{1}{2})^3 = \frac{1}{24}$. - If the die shows $3$, Snuke needs to get two consecutive heads from two coin flips to obtain a score of $10$ or above. The probability of this happening is $\frac{1}{3} \times (\frac{1}{2})^2 = \frac{1}{12}$. Thus, the probability that Snuke wins is $\frac{1}{48} + \frac{1}{24} + \frac{1}{12} = \frac{7}{48} \simeq 0.1458333333$.
Input #2
100000 5
Output #2
0.999973749998
题目信息
题号
abc126_c
时间限制
2 s
内存限制
1024 MB

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