AtCoder Beginner Contest 158
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Problem Statement
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Takahashi has a string $S$ consisting of lowercase English letters.
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Starting with this string, he will produce a new one in the procedure given as follows.
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The procedure consists of $Q$ operations. In Operation $i$ $(1 \leq i \leq Q)$, an integer $T_i$ is provided, which means the following:
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- If
$T_i = 1$: reverse the string$S$. - If
$T_i = 2$: An integer$F_i$and a lowercase English letter$C_i$are additionally provided. - If
$F_i = 1$: Add$C_i$to the beginning of the string$S$.- If
$F_i = 2$: Add$C_i$to the end of the string$S$.
- If
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Help Takahashi by finding the final string that results from the procedure.
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Constraints
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$1 \leq |S| \leq 10^5$$S$consists of lowercase English letters.$1 \leq Q \leq 2 \times 10^5$$T_i = 1$or$2$.$F_i = 1$or$2$, if provided.$C_i$is a lowercase English letter, if provided.
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Input
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Input is given from Standard Input in the following format:
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S
Q
Query_1
:
Query_Q
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In the $3$-rd through the $(Q+2)$-th lines, $Query_i$ is one of the following:
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1
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which means $T_i = 1$, and:
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2 F_i C_i
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which means $T_i = 2$.
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Output
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Print the resulting string.
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样例
Input #1
a
4
2 1 p
1
2 2 c
1
Output #1
cpa
There will be $Q = 4$ operations. Initially, $S$ is `a`.
- Operation $1$: Add `p` at the beginning of $S$. $S$ becomes `pa`.
- Operation $2$: Reverse $S$. $S$ becomes `ap`.
- Operation $3$: Add `c` at the end of $S$. $S$ becomes `apc`.
- Operation $4$: Reverse $S$. $S$ becomes `cpa`.
Thus, the resulting string is `cpa`.
Input #2
a
6
2 2 a
2 1 b
1
2 2 c
1
1
Output #2
aabc
There will be $Q = 6$ operations. Initially, $S$ is `a`.
- Operation $1$: $S$ becomes `aa`.
- Operation $2$: $S$ becomes `baa`.
- Operation $3$: $S$ becomes `aab`.
- Operation $4$: $S$ becomes `aabc`.
- Operation $5$: $S$ becomes `cbaa`.
- Operation $6$: $S$ becomes `aabc`.
Thus, the resulting string is `aabc`.
Input #3
y
1
2 1 x
Output #3
xy
题目信息
题面与样例版权归 AtCoder 及出题人所有;中文翻译由 AI 生成(CI 管线),如有出入请以原文为准。