AtCoder Beginner Contest 190
E
Magical Ornament
AtCoder
⌀ 1645
原题
← DF →
翻译中…

Problem Statement

翻译中…

There are $N$ kinds of magical gems, numbered $1, 2, \ldots, N$, distributed in the AtCoder Kingdom. Takahashi is trying to make an ornament by arranging gems in a row. For some pairs of gems, we can put the two gems next to each other; for other pairs, we cannot. We have $M$ pairs for which the two gems can be adjacent: (Gem $A_1$, Gem $B_1$), (Gem $A_2$, Gem $B_2$), $\ldots$, (Gem $A_M$, Gem $B_M$). For the other pairs, the two gems cannot be adjacent. (Order does not matter in these pairs.) Determine whether it is possible to form a sequence of gems that has one or more gems of each of the kinds $C_1, C_2, \dots, C_K$. If the answer is yes, find the minimum number of stones needed to form such a sequence.

翻译中…

Constraints

翻译中…
  • All values in input are integers.
  • $1 ≤ N ≤ 10^5$
  • $0 ≤ M ≤ 10^5$
  • $1 ≤ A_i < B_i ≤ N$
  • If $i ≠ j$, $(A_i, B_i) ≠ (A_j, B_j)$.
  • $1 ≤ K ≤ 17$
  • $1 ≤ C_1 < C_2 < \dots < C_K ≤ N$
翻译中…

Input

翻译中…

Input is given from Standard Input in the following format:

翻译中…

N M
A_1 B_1
A_2 B_2
\hspace{7mm}\vdots
A_M B_M
K
C_1 C_2 \cdots C_K

翻译中…

Output

翻译中…

Print the minimum number of stones needed to form a sequence of gems that has one or more gems of each of the kinds $C_1, C_2, \dots, C_K$. If such a sequence cannot be formed, print -1 instead.

翻译中…

样例

Input #1
4 3
1 4
2 4
3 4
3
1 2 3
Output #1
5
For example, by arranging the gems in the order $[1, 4, 2, 4, 3]$, we can form a sequence of length $5$ with Gems $1, 2, 3$.
Input #2
4 3
1 4
2 4
1 2
3
1 2 3
Output #2
-1
Input #3
10 10
3 9
3 8
8 10
2 10
5 8
6 8
5 7
6 7
1 6
2 4
4
1 2 7 9
Output #3
11
For example, by arranging the gems in the order $[1, 6, 7, 5, 8, 3, 9, 3, 8, 10, 2]$, we can form a sequence of length $11$ with Gems $1, 2, 7, 9$.
题目信息
题号
abc190_e
时间限制
2 s
内存限制
1024 MB

题面与样例版权归 AtCoder 及出题人所有;中文翻译由 AI 生成(CI 管线),如有出入请以原文为准。