パナソニックプログラミングコンテスト(AtCoder Beginner Contest 195)
翻译中…
Problem Statement
翻译中…
We have $N$ pieces of baggage called Baggage $1$ through $N$, and $M$ boxes called Box $1$ through $M$.
翻译中…
Baggage $i$ has a size of $W_i$ and a value of $V_i$.
翻译中…
Box $i$ can contain a piece of baggage whose size of at most $X_i$. It cannot contain two or more pieces of baggage.
翻译中…
You will be given $Q$ queries. In each query, given two integers $L$ and $R$, solve the following problem:
翻译中…
- Problem: Out of the
$M$boxes,$R-L+1$boxes, Box$L,L+1,\ldots,R$, have become unavailable. Find the maximum possible total value of a set of baggage that we can put into the remaining boxes simultaneously.
翻译中…
Constraints
翻译中…
$1 \leq N \leq 50$$1 \leq M \leq 50$$1 \leq Q \leq 50$$1 \leq W_i \leq 10^6$$1 \leq V_i \leq 10^6$$1 \leq X_i \leq 10^6$$1 \leq L \leq R \leq M$- All values in input are integers.
翻译中…
Input
翻译中…
Input is given from Standard Input in the following format:
翻译中…
N M Q
W_1 V_1
\vdots
W_N V_N
X_1 \ldots X_M
\mathrm{Query}_1
\vdots
\mathrm{Query}_Q
翻译中…
Each Query is in the following format:
翻译中…
L R
翻译中…
Output
翻译中…
Print $Q$ lines.
翻译中…
The $i$-th line should contain the answer to the problem described by $\mathrm{Query}_i$.
翻译中…
样例
Input #1
3 4 3
1 9
5 3
7 8
1 8 6 9
4 4
1 4
1 3
Output #1
20
0
9
In the $1$-st query, only Box $4$ is unavailable. By putting Baggage $1$ into Box $1$, Baggage $3$ into Box $2$, and Baggage $2$ into Box $3$, we can put all baggage into boxes, making the total value of baggage in boxes $20$.
In the $2$-nd query, all boxes are unavailable; the answer is $0$.
In the $3$-rd query, only Box $4$ is available. By putting Baggage $1$ into Box $4$, we can make the total value of baggage in boxes $9$, which is the maximum possible result.
题目信息
题面与样例版权归 AtCoder 及出题人所有;中文翻译由 AI 生成(CI 管线),如有出入请以原文为准。