AtCoder Beginner Contest 203(Sponsored by Panasonic)
E
White Pawn
AtCoder
⌀ 1750
原题
← DF →
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Problem Statement

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Let $N$ be a positive integer. We have a $(2N+1)\times (2N+1)$ grid where rows are numbered $0$ through $2N$ and columns are also numbered $0$ through $2N$. Let $(i,j)$ denote the square at Row $i$ and Column $j$.

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We have one white pawn, which is initially at $(0, N)$. Also, we have $M$ black pawns, the $i$-th of which is at $(X_i, Y_i)$.

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When the white pawn is at $(i, j)$, you can do one of the following operations to move it:

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  • If $0\leq i\leq 2N-1$, $0 \leq j\leq 2N$ hold and $(i+1,j)$ does not contain a black pawn, move the white pawn to $(i+1, j)$.
  • If $0\leq i\leq 2N-1$, $0 \leq j\leq 2N-1$ hold and $(i+1,j+1)$ does contain a black pawn, move the white pawn to $(i+1,j+1)$.
  • If $0\leq i\leq 2N-1$, $1 \leq j\leq 2N$ hold and $(i+1,j-1)$ does contain a black pawn, move the white pawn to $(i+1,j-1)$.
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You cannot move the black pawns.

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Find the number of integers $Y$ such that it is possible to have the white pawn at $(2N, Y)$ by repeating these operations.

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Constraints

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  • $1 \leq N \leq 10^9$
  • $0 \leq M \leq 2\times 10^5$
  • $1 \leq X_i \leq 2N$
  • $0 \leq Y_i \leq 2N$
  • $(X_i, Y_i) \neq (X_j, Y_j)$ $(i \neq j)$
  • All values in input are integers.
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Input

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Input is given from Standard Input in the following format:

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N M
X_1 Y_1
:
X_M Y_M

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Output

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Print the answer.

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样例

Input #1
2 4
1 1
1 2
2 0
4 2
Output #1
3
We can move the white pawn to $(4,0)$, $(4,1)$, and $(4,2)$, as follows: - $(0,2)\to (1,1)\to (2,1)\to (3,1)\to (4,2)$ - $(0,2)\to (1,1)\to (2,1)\to (3,1)\to (4,1)$ - $(0,2)\to (1,1)\to (2,0)\to (3,0)\to (4,0)$ On the other hand, we cannot move it to $(4,3)$ or $(4,4)$. Thus, we should print $3$.
Input #2
1 1
1 1
Output #2
0
We cannot move the white pawn from $(0,1)$.
题目信息
题号
abc203_e
时间限制
2 s
内存限制
1024 MB

题面与样例版权归 AtCoder 及出题人所有;中文翻译由 AI 生成(CI 管线),如有出入请以原文为准。