Toyota Programming Contest 2023 Spring Qual B(AtCoder Beginner Contest 290)
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Problem Statement
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There are $N$ dogs numbered $1$ through $N$ and $M$ cats numbered $1$ through $M$. You will arrange the $(N+M)$ animals in a line from left to right. An arrangement causes each animal's frustration as follows:
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- The frustration of dog
$i$is$A_i\times|x-y|$, where$x$and$y$are the numbers of cats to the left and right of that dog, respectively. - The frustration of cat
$i$is$B_i\times|x-y|$, where$x$and$y$are the numbers of dogs to the left and right of that cat, respectively.
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Find the minimum possible sum of the frustrations.
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Constraints
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$1\leq N,M \leq 300$$1\leq A_i,B_i \leq 10^9$- All values in the input are integers.
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Input
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The input is given from Standard Input in the following format:
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N M
A_1 A_2 \ldots A_N
B_1 B_2 \ldots B_M
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Output
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Print the answer as an integer.
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样例
Input #1
2 2
1 3
2 4
Output #1
6
Consider the following arrangement: dog $1$, cat $2$, dog $2$, cat $1$, from left to right. Then,
- dog $1$'s frustration is $1\times|0-2|=2$;
- dog $2$'s frustration is $3\times|1-1|=0$;
- cat $1$'s frustration is $2\times|2-0|=4$; and
- cat $2$'s frustration is $4\times|1-1|=0$,
so the sum of the frustrations is $6$. Rearranging the animals does not make the sum less than $6$, so the answer is $6$.
Input #2
1 2
100
100 290
Output #2
390
Input #3
5 7
522 575 426 445 772
81 447 629 497 202 775 325
Output #3
13354
题目信息
题号
abc290_h
时间限制
2 s
内存限制
1024 MB
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