AtCoder Grand Contest 023
F
01 on Tree
AtCoder
⌀ 3148
原题
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Problem Statement

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Snuke has a rooted tree with $N$ vertices, numbered $1$ through $N$. Vertex $1$ is the root of the tree, and the parent of Vertex $i$ ( $2\leq i \leq N$ ) is Vertex $P_i$ ( $P_i < i$ ). There is a number, $0$ or $1$, written on each vertex. The number written on Vertex $i$ is $V_i$.

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Snuke would like to arrange the vertices of this tree in a horizontal row. Here, for every vertex, there should be no ancestor of that vertex to the right of that vertex.

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After arranging the vertices, let $X$ be the sequence obtained by reading the numbers written on the vertices from left to right in the arrangement. Snuke would like to minimize the inversion number of $X$. Find the minimum possible inversion number of $X$.

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Note

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The inversion number of a sequence $Z$ whose length $N$ is the number of pairs of integers $i$ and $j$ ( $1 \leq i < j \leq N$ ) such that $Z_i > Z_j$.

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Constraints

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  • $1 \leq N \leq 2 \times 10^5$
  • $1 \leq P_i < i$ ( $2 \leq i \leq N$ )
  • $0 \leq V_i \leq 1$ ( $1 \leq i \leq N$ )
  • All values in input are integers.
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Input

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Input is given from Standard Input in the following format:

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N
P_2 P_3 ... P_N
V_1 V_2 ... V_N

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Output

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Print the minimum possible inversion number of $X$.

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样例

Input #1
6
1 1 2 3 3
0 1 1 0 0 0
Output #1
4
When the vertices are arranged in the order $1, 3, 5, 6, 2, 4$, $X$ will be $(0, 1, 0, 0, 1, 0)$, whose inversion number is $4$. It is impossible to have fewer inversions, so the answer is $4$.
Input #2
1

0
Output #2
0
$X = (0)$, whose inversion number is $0$.
Input #3
15
1 2 3 2 5 6 2 2 9 10 1 12 13 12
1 1 1 0 1 1 0 0 1 0 0 1 1 0 0
Output #3
31
题目信息
题号
agc023_f
时间限制
2 s
内存限制
256 MB

题面与样例版权归 AtCoder 及出题人所有;中文翻译由 AI 生成(CI 管线),如有出入请以原文为准。