AtCoder Grand Contest 032
D
Rotation Sort
AtCoder
⌀ 2602
原题
← CE →
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Problem Statement

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You are given a permutation $p = (p_1, \ldots, p_N)$ of $\{ 1, \ldots, N \}$. You can perform the following two kinds of operations repeatedly in any order:

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  • Pay a cost $A$. Choose integers $l$ and $r$ ($1 \leq l < r \leq N$), and shift $(p_l, \ldots, p_r)$ to the left by one. That is, replace $p_l, p_{l + 1}, \ldots, p_{r - 1}, p_r$ with $p_{l + 1}, p_{l + 2}, \ldots, p_r, p_l$, respectively.
  • Pay a cost $B$. Choose integers $l$ and $r$ ($1 \leq l < r \leq N$), and shift $(p_l, \ldots, p_r)$ to the right by one. That is, replace $p_l, p_{l + 1}, \ldots, p_{r - 1}, p_r$ with $p_r, p_l, \ldots, p_{r - 2}, p_{r - 1}$, respectively.
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Find the minimum total cost required to sort $p$ in ascending order.

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Constraints

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  • All values in input are integers.
  • $1 \leq N \leq 5000$
  • $1 \leq A, B \leq 10^9$
  • $(p_1 \ldots, p_N)$ is a permutation of $\{ 1, \ldots, N \}$.
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Input

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Input is given from Standard Input in the following format:

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N A B
p_1 \cdots p_N

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Output

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Print the minimum total cost required to sort $p$ in ascending order.

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样例

Input #1
3 20 30
3 1 2
Output #1
20
Shifting $(p_1, p_2, p_3)$ to the left by one results in $p = (1, 2, 3)$.
Input #2
4 20 30
4 2 3 1
Output #2
50
One possible sequence of operations is as follows: - Shift $(p_1, p_2, p_3, p_4)$ to the left by one. Now we have $p = (2, 3, 1, 4)$. - Shift $(p_1, p_2, p_3)$ to the right by one. Now we have $p = (1, 2, 3, 4)$. Here, the total cost is $20 + 30 = 50$.
Input #3
1 10 10
1
Output #3
0
Input #4
4 1000000000 1000000000
4 3 2 1
Output #4
3000000000
Input #5
9 40 50
5 3 4 7 6 1 2 9 8
Output #5
220
题目信息
题号
agc032_d
时间限制
2 s
内存限制
1024 MB

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