Problem Statement
You are given a positive integer $N$ and a sequence $A = (A_0, A_1, \ldots, A_{2^N-1})$ of $2^N$ terms, where each $A_i$ is an integer between $0$ and $2^N-1$ (inclusive) and $A_i\neq A_j$ holds if $i\neq j$.
You can perform the following two kinds of operations on $A$:
- Operation
$+$: For every$i$, change$A_i$to$(A_i + 1) \bmod 2^N$. - Operation
$\oplus$: Choose an integer$x$between$0$and$2^N-1$. For every$i$, change$A_i$to$A_i\oplus x$.
Here, $\oplus$ denotes bitwise $\mathrm{XOR}$.
What is bitwise $\mathrm{XOR}$? The bitwise $\mathrm{XOR}$ of non-negative integers $A$ and $B$, $A \oplus B$, is defined as follows: When $A \oplus B$ is written in base two, the digit in the $2^k$'s place ($k \geq 0$) is $1$ if exactly one of $A$ and $B$ is $1$, and $0$ otherwise. For example, we have $3 \oplus 5 = 6$ (in base two: $011 \oplus 101 = 110$).
Your objective is to make $A_i = i$ for every $i$. Determine whether it is achievable. It can be proved that, under the Constraints of this problem, one can achieve the objective with at most $10^6$ operations if it is achievable at all. Print such a sequence of operations.
Constraints
$1\leq N\leq 18$$0\leq A_i \leq 2^N - 1$$A_i\neq A_j$, if$i\neq j$
Input
Input is given from Standard Input in the following format:
N
A_0 A_1 \ldots A_{2^N - 1}
Output
If it is possible to make $A_i = i$ for every $i$, print Yes; otherwise, print No.
In the case of Yes, it should be followed by a sequence of operations that achieves the objective, in the following format:
K
x_1 x_2 \ldots x_K
Here, $K$ is a non-negative integer representing the number of operations, which must satisfy $0\leq K\leq 10^6$; $x_i$ is an integer representing the $i$-th operation, which should be set as follows.
- If the
$i$-th operation is Operation$+$,$x_i=-1$. - If the
$i$-th operation is Operation$\oplus$,$x_i$should be the integer chosen in that operation.
If there are multiple possible solutions, you may print any of them.
样例
3
5 0 3 6 1 4 7 2
Yes
4
-1 6 -1 1
3
2 5 4 3 6 1 0 7
No
3
0 1 2 3 4 5 6 7
Yes
0
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