AtCoder Regular Contest 117
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Problem Statement
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A sequence of length $A + B$, $E = (E_1, E_2, \dots, E_{A+B})$, that satisfies all of the conditions below is said to be a god sequence.
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$E_1 + E_2 + \cdots + E_{A+B} = 0$holds.- There are exactly
$A$positive integers among$E_1, E_2, \dots, E_{A+B}$. - There are exactly
$B$negative integers among$E_1, E_2, \dots, E_{A+B}$. $E_1, E_2, \dots, E_{A+B}$are all distinct.$-10^{9} \leq E_i \leq 10^9, E_i \neq 0$holds for every$i$$(1 \leq i \leq A+B)$.
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Construct one god sequence.
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We can prove that at least one god sequence exists under Constraints of this problem.
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Constraints
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$1 \leq A \leq 1000$$1 \leq B \leq 1000$- All values in input are integers.
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Input
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Input is given from Standard Input in the following format:
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A B
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Output
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Print the elements of your sequence in one line, with space as separator.
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If there are multiple god sequences, any of them will be accepted.
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E_1 E_2 \cdots E_{A+B}
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样例
Input #1
1 1
Output #1
1001 -1001
A sequence $(1001, -1001)$ contains $A=1$ positive integer and $B=1$ negative integer totaling $1001+(-1001)=0$.
It also satisfies the other conditions and thus is a god sequence.
Input #2
1 4
Output #2
-8 -6 -9 120 -97
A sequence $(-8, -6, -9, 120, -97)$ contains $A=1$ positive integer and $B=4$ negative integers totaling $(-8)+(-6)+(-9)+120+(-97)=0$.
It also satisfies the other conditions and thus is a god sequence.
Input #3
7 5
Output #3
323 -320 411 206 -259 298 -177 -564 167 392 -628 151
题目信息
题面与样例版权归 AtCoder 及出题人所有;中文翻译由 AI 生成(CI 管线),如有出入请以原文为准。