Codeforces Round 505 (rated, Div. 1 + Div. 2, based on VK Cup 2018 Final)
B
Weakened Common Divisor
Codeforces
1600
原题
← AC →
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During the research on properties of the greatest common divisor (GCD) of a set of numbers, Ildar, a famous mathematician, introduced a brand new concept of the weakened common divisor (WCD) of a list of pairs of integers.

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For a given list of pairs of integers $(a_1, b_1)$, $(a_2, b_2)$, ..., $(a_n, b_n)$ their WCD is arbitrary integer greater than $1$, such that it divides at least one element in each pair. WCD may not exist for some lists.

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For example, if the list looks like $[(12, 15), (25, 18), (10, 24)]$, then their WCD can be equal to $2$, $3$, $5$ or $6$ (each of these numbers is strictly greater than $1$ and divides at least one number in each pair).

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You're currently pursuing your PhD degree under Ildar's mentorship, and that's why this problem was delegated to you. Your task is to calculate WCD efficiently.

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Input

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The first line contains a single integer $n$ ($1 \le n \le 150\,000$) — the number of pairs.

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Each of the next $n$ lines contains two integer values $a_i$, $b_i$ ($2 \le a_i, b_i \le 2 \cdot 10^9$).

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Output

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Print a single integer — the WCD of the set of pairs.

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If there are multiple possible answers, output any; if there is no answer, print $-1$.

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Note

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In the first example the answer is $6$ since it divides $18$ from the first pair, $24$ from the second and $12$ from the third ones. Note that other valid answers will also be accepted.

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In the second example there are no integers greater than $1$ satisfying the conditions.

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In the third example one of the possible answers is $5$. Note that, for example, $15$ is also allowed, but it's not necessary to maximize the output.

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样例

Input #1
3
17 18
15 24
12 15
Output #1
6
InputCopy OutputCopy
Input #2
2
10 16
7 17
Output #2
-1
InputCopy OutputCopy
Input #3
5
90 108
45 105
75 40
165 175
33 30
Output #3
5
InputCopy OutputCopy
题目信息
题号
1025B
时间限制
1.5 s
内存限制
256 MB
标签
暴力
贪心
数论

题面与样例版权归 Codeforces 及出题人所有;中文翻译由 AI 生成(CI 管线),如有出入请以原文为准。