Mail.Ru Cup 2018 Round 2
E
Segments on the Line
Codeforces
2500
原题
← DF →
翻译中…

You are a given a list of integers $a_1, a_2, \ldots, a_n$ and $s$ of its segments $[l_j; r_j]$ (where $1 \le l_j \le r_j \le n$).

翻译中…

You need to select exactly $m$ segments in such a way that the $k$-th order statistic of the multiset of $a_i$, where $i$ is contained in at least one segment, is the smallest possible. If it's impossible to select a set of $m$ segments in such a way that the multiset contains at least $k$ elements, print -1.

翻译中…

The $k$-th order statistic of a multiset is the value of the $k$-th element after sorting the multiset in non-descending order.

翻译中…

Input

翻译中…

The first line contains four integers $n$, $s$, $m$ and $k$ ($1 \le m \le s \le 1500$, $1 \le k \le n \le 1500$) — the size of the list, the number of segments, the number of segments to choose and the statistic number.

翻译中…

The second line contains $n$ integers $a_i$ ($1 \le a_i \le 10^9$) — the values of the numbers in the list.

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Each of the next $s$ lines contains two integers $l_i$ and $r_i$ ($1 \le l_i \le r_i \le n$) — the endpoints of the segments.

翻译中…

It is possible that some segments coincide.

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Output

翻译中…

Print exactly one integer — the smallest possible $k$-th order statistic, or -1 if it's impossible to choose segments in a way that the multiset contains at least $k$ elements.

翻译中…

Note

翻译中…

In the first example, one possible solution is to choose the first and the third segment. Together they will cover three elements of the list (all, except for the third one). This way the $2$-nd order statistic for the covered elements is $2$.

翻译中…

image

翻译中…

样例

Input #1
4 3 2 2
3 1 3 2
1 2
2 3
4 4
Output #1
2
InputCopy OutputCopy
Input #2
5 2 1 1
1 2 3 4 5
2 4
1 5
Output #2
1
InputCopy OutputCopy
Input #3
5 3 3 5
5 5 2 1 1
1 2
2 3
3 4
Output #3
-1
InputCopy OutputCopy
题目信息
题号
1055E
时间限制
2 s
内存限制
256 MB
标签
二分
动态规划

题面与样例版权归 Codeforces 及出题人所有;中文翻译由 AI 生成(CI 管线),如有出入请以原文为准。