Codeforces Round 534 (Div. 2)
A
Splitting into digits
Codeforces
800
原题
←B →
翻译中…

Vasya has his favourite number $n$. He wants to split it to some non-zero digits. It means, that he wants to choose some digits $d_1, d_2, \ldots, d_k$, such that $1 \leq d_i \leq 9$ for all $i$ and $d_1 + d_2 + \ldots + d_k = n$.

翻译中…

Vasya likes beauty in everything, so he wants to find any solution with the minimal possible number of different digits among $d_1, d_2, \ldots, d_k$. Help him!

翻译中…

Input

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The first line contains a single integer $n$ — the number that Vasya wants to split ($1 \leq n \leq 1000$).

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Output

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In the first line print one integer $k$ — the number of digits in the partition. Note that $k$ must satisfy the inequality $1 \leq k \leq n$. In the next line print $k$ digits $d_1, d_2, \ldots, d_k$ separated by spaces. All digits must satisfy the inequalities $1 \leq d_i \leq 9$.

翻译中…

You should find a partition of $n$ in which the number of different digits among $d_1, d_2, \ldots, d_k$ will be minimal possible among all partitions of $n$ into non-zero digits. Among such partitions, it is allowed to find any. It is guaranteed that there exists at least one partition of the number $n$ into digits.

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Note

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In the first test, the number $1$ can be divided into $1$ digit equal to $1$.

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In the second test, there are $3$ partitions of the number $4$ into digits in which the number of different digits is $1$. This partitions are $[1, 1, 1, 1]$, $[2, 2]$ and $[4]$. Any of these partitions can be found. And, for example, dividing the number $4$ to the digits $[1, 1, 2]$ isn't an answer, because it has $2$ different digits, that isn't the minimum possible number.

翻译中…

样例

Input #1
1
Output #1
1
1
InputCopy OutputCopy
Input #2
4
Output #2
2
2 2
InputCopy OutputCopy
Input #3
27
Output #3
3
9 9 9
InputCopy OutputCopy
题目信息
题号
1104A
时间限制
1 s
内存限制
256 MB
标签
构造
模拟
数学

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