Codeforces Round 557 (Div. 2) [based on Forethought Future Cup - Final Round]
A
Zoning Restrictions Again
Codeforces
800
原题
←B →
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You are planning to build housing on a street. There are $n$ spots available on the street on which you can build a house. The spots are labeled from $1$ to $n$ from left to right. In each spot, you can build a house with an integer height between $0$ and $h$.

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In each spot, if a house has height $a$, you will gain $a^2$ dollars from it.

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The city has $m$ zoning restrictions. The $i$-th restriction says that the tallest house from spots $l_i$ to $r_i$ (inclusive) must be at most $x_i$.

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You would like to build houses to maximize your profit. Determine the maximum profit possible.

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Input

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The first line contains three integers $n$, $h$, and $m$ ($1 \leq n,h,m \leq 50$) — the number of spots, the maximum height, and the number of restrictions.

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Each of the next $m$ lines contains three integers $l_i$, $r_i$, and $x_i$ ($1 \leq l_i \leq r_i \leq n$, $0 \leq x_i \leq h$) — left and right limits (inclusive) of the $i$-th restriction and the maximum possible height in that range.

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Output

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Print a single integer, the maximum profit you can make.

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Note

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In the first example, there are $3$ houses, the maximum height of a house is $3$, and there are $3$ restrictions. The first restriction says the tallest house between $1$ and $1$ must be at most $1$. The second restriction says the tallest house between $2$ and $2$ must be at most $3$. The third restriction says the tallest house between $3$ and $3$ must be at most $2$.

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In this case, it is optimal to build houses with heights $[1, 3, 2]$. This fits within all the restrictions. The total profit in this case is $1^2 + 3^2 + 2^2 = 14$.

翻译中…

In the second example, there are $4$ houses, the maximum height of a house is $10$, and there are $2$ restrictions. The first restriction says the tallest house from $2$ to $3$ must be at most $8$. The second restriction says the tallest house from $3$ to $4$ must be at most $7$.

翻译中…

In this case, it's optimal to build houses with heights $[10, 8, 7, 7]$. We get a profit of $10^2+8^2+7^2+7^2 = 262$. Note that there are two restrictions on house $3$ and both of them must be satisfied. Also, note that even though there isn't any explicit restrictions on house $1$, we must still limit its height to be at most $10$ ($h=10$).

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样例

Input #1
3 3 3
1 1 1
2 2 3
3 3 2
Output #1
14
InputCopy OutputCopy
Input #2
4 10 2
2 3 8
3 4 7
Output #2
262
InputCopy OutputCopy
题目信息
题号
1162A
时间限制
1 s
内存限制
256 MB
标签
模拟

题面与样例版权归 Codeforces 及出题人所有;中文翻译由 AI 生成(CI 管线),如有出入请以原文为准。