Codeforces Round 581 (Div. 2)
C
Anna, Svyatoslav and Maps
Codeforces
1700
原题
← BD1 →
翻译中…

The main characters have been omitted to be short.

翻译中…

You are given a directed unweighted graph without loops with $n$ vertexes and a path in it (that path is not necessary simple) given by a sequence $p_1, p_2, \ldots, p_m$ of $m$ vertexes; for each $1 \leq i \lt m$ there is an arc from $p_i$ to $p_{i+1}$.

翻译中…

Define the sequence $v_1, v_2, \ldots, v_k$ of $k$ vertexes as good, if $v$ is a subsequence of $p$, $v_1 = p_1$, $v_k = p_m$, and $p$ is one of the shortest paths passing through the vertexes $v_1$, $\ldots$, $v_k$ in that order.

翻译中…

A sequence $a$ is a subsequence of a sequence $b$ if $a$ can be obtained from $b$ by deletion of several (possibly, zero or all) elements. It is obvious that the sequence $p$ is good but your task is to find the shortest good subsequence.

翻译中…

If there are multiple shortest good subsequences, output any of them.

翻译中…

Input

翻译中…

The first line contains a single integer $n$ ($2 \le n \le 100$) — the number of vertexes in a graph.

翻译中…

The next $n$ lines define the graph by an adjacency matrix: the $j$-th character in the $i$-st line is equal to $1$ if there is an arc from vertex $i$ to the vertex $j$ else it is equal to $0$. It is guaranteed that the graph doesn't contain loops.

翻译中…

The next line contains a single integer $m$ ($2 \le m \le 10^6$) — the number of vertexes in the path.

翻译中…

The next line contains $m$ integers $p_1, p_2, \ldots, p_m$ ($1 \le p_i \le n$) — the sequence of vertexes in the path. It is guaranteed that for any $1 \leq i \lt m$ there is an arc from $p_i$ to $p_{i+1}$.

翻译中…

Output

翻译中…

In the first line output a single integer $k$ ($2 \leq k \leq m$) — the length of the shortest good subsequence. In the second line output $k$ integers $v_1$, $\ldots$, $v_k$ ($1 \leq v_i \leq n$) — the vertexes in the subsequence. If there are multiple shortest subsequences, print any. Any two consecutive numbers should be distinct.

翻译中…

Note

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Below you can see the graph from the first example:

翻译中…

image

翻译中…

The given path is passing through vertexes $1$, $2$, $3$, $4$. The sequence $1-2-4$ is good because it is the subsequence of the given path, its first and the last elements are equal to the first and the last elements of the given path respectively, and the shortest path passing through vertexes $1$, $2$ and $4$ in that order is $1-2-3-4$. Note that subsequences $1-4$ and $1-3-4$ aren't good because in both cases the shortest path passing through the vertexes of these sequences is $1-3-4$.

翻译中…

In the third example, the graph is full so any sequence of vertexes in which any two consecutive elements are distinct defines a path consisting of the same number of vertexes.

翻译中…

In the fourth example, the paths $1-2-4$ and $1-3-4$ are the shortest paths passing through the vertexes $1$ and $4$.

翻译中…

样例

Input #1
4
0110
0010
0001
1000
4
1 2 3 4
Output #1
3
1 2 4
InputCopy OutputCopy
Input #2
4
0110
0010
1001
1000
20
1 2 3 4 1 2 3 4 1 2 3 4 1 2 3 4 1 2 3 4
Output #2
11
1 2 4 2 4 2 4 2 4 2 4
InputCopy OutputCopy
Input #3
3
011
101
110
7
1 2 3 1 3 2 1
Output #3
7
1 2 3 1 3 2 1
InputCopy OutputCopy
Input #4
4
0110
0001
0001
1000
3
1 2 4
Output #4
2
1 4
InputCopy OutputCopy
题目信息
题号
1204C
时间限制
2 s
内存限制
256 MB
标签
动态规划
图论
贪心
最短路

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