Technocup 2020 - Elimination Round 1
C
Save the Nature
Codeforces
1600
原题
← BD →
翻译中…

You are an environmental activist at heart but the reality is harsh and you are just a cashier in a cinema. But you can still do something!

翻译中…

You have $n$ tickets to sell. The price of the $i$-th ticket is $p_i$. As a teller, you have a possibility to select the order in which the tickets will be sold (i.e. a permutation of the tickets). You know that the cinema participates in two ecological restoration programs applying them to the order you chose:

翻译中…
  • The $x\%$ of the price of each the $a$-th sold ticket ($a$-th, $2a$-th, $3a$-th and so on) in the order you chose is aimed for research and spreading of renewable energy sources.
  • The $y\%$ of the price of each the $b$-th sold ticket ($b$-th, $2b$-th, $3b$-th and so on) in the order you chose is aimed for pollution abatement.
翻译中…

If the ticket is in both programs then the $(x + y) \%$ are used for environmental activities. Also, it's known that all prices are multiples of $100$, so there is no need in any rounding.

翻译中…

For example, if you'd like to sell tickets with prices $[400, 100, 300, 200]$ and the cinema pays $10\%$ of each $2$-nd sold ticket and $20\%$ of each $3$-rd sold ticket, then arranging them in order $[100, 200, 300, 400]$ will lead to contribution equal to $100 \cdot 0 + 200 \cdot 0.1 + 300 \cdot 0.2 + 400 \cdot 0.1 = 120$. But arranging them in order $[100, 300, 400, 200]$ will lead to $100 \cdot 0 + 300 \cdot 0.1 + 400 \cdot 0.2 + 200 \cdot 0.1 = 130$.

翻译中…

Nature can't wait, so you decided to change the order of tickets in such a way, so that the total contribution to programs will reach at least $k$ in minimum number of sold tickets. Or say that it's impossible to do so. In other words, find the minimum number of tickets which are needed to be sold in order to earn at least $k$.

翻译中…

Input

翻译中…

The first line contains a single integer $q$ ($1 \le q \le 100$) — the number of independent queries. Each query consists of $5$ lines.

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The first line of each query contains a single integer $n$ ($1 \le n \le 2 \cdot 10^5$) — the number of tickets.

翻译中…

The second line contains $n$ integers $p_1, p_2, \dots, p_n$ ($100 \le p_i \le 10^9$, $p_i \bmod 100 = 0$) — the corresponding prices of tickets.

翻译中…

The third line contains two integers $x$ and $a$ ($1 \le x \le 100$, $x + y \le 100$, $1 \le a \le n$) — the parameters of the first program.

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The fourth line contains two integers $y$ and $b$ ($1 \le y \le 100$, $x + y \le 100$, $1 \le b \le n$) — the parameters of the second program.

翻译中…

The fifth line contains single integer $k$ ($1 \le k \le 10^{14}$) — the required total contribution.

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It's guaranteed that the total number of tickets per test doesn't exceed $2 \cdot 10^5$.

翻译中…

Output

翻译中…

Print $q$ integers — one per query.

翻译中…

For each query, print the minimum number of tickets you need to sell to make the total ecological contribution of at least $k$ if you can sell tickets in any order.

翻译中…

If the total contribution can not be achieved selling all the tickets, print $-1$.

翻译中…

Note

翻译中…

In the first query the total contribution is equal to $50 + 49 = 99 \lt 100$, so it's impossible to gather enough money.

翻译中…

In the second query you can rearrange tickets in a following way: $[100, 100, 200, 200, 100, 200, 100, 100]$ and the total contribution from the first $6$ tickets is equal to $100 \cdot 0 + 100 \cdot 0.1 + 200 \cdot 0.15 + 200 \cdot 0.1 + 100 \cdot 0 + 200 \cdot 0.25 = 10 + 30 + 20 + 50 = 110$.

翻译中…

In the third query the full price of each ticket goes to the environmental activities.

翻译中…

In the fourth query you can rearrange tickets as $[100, 200, 100, 100, 100]$ and the total contribution from the first $4$ tickets is $100 \cdot 0 + 200 \cdot 0.31 + 100 \cdot 0 + 100 \cdot 0.31 = 62 + 31 = 93$.

翻译中…

样例

Input #1
4
1
100
50 1
49 1
100
8
100 200 100 200 100 200 100 100
10 2
15 3
107
3
1000000000 1000000000 1000000000
50 1
50 1
3000000000
5
200 100 100 100 100
69 5
31 2
90
Output #1
-1
6
3
4
InputCopy OutputCopy
题目信息
题号
1223C
时间限制
2 s
内存限制
256 MB
标签
二分
贪心

题面与样例版权归 Codeforces 及出题人所有;中文翻译由 AI 生成(CI 管线),如有出入请以原文为准。