Grakn Forces 2020
D
Searchlights
Codeforces
2000
原题
← CE →
翻译中…

There are $n$ robbers at coordinates $(a_1, b_1)$, $(a_2, b_2)$, ..., $(a_n, b_n)$ and $m$ searchlight at coordinates $(c_1, d_1)$, $(c_2, d_2)$, ..., $(c_m, d_m)$.

翻译中…

In one move you can move each robber to the right (increase $a_i$ of each robber by one) or move each robber up (increase $b_i$ of each robber by one). Note that you should either increase all $a_i$ or all $b_i$, you can't increase $a_i$ for some points and $b_i$ for some other points.

翻译中…

Searchlight $j$ can see a robber $i$ if $a_i \leq c_j$ and $b_i \leq d_j$.

翻译中…

A configuration of robbers is safe if no searchlight can see a robber (i.e. if there is no pair $i,j$ such that searchlight $j$ can see a robber $i$).

翻译中…

What is the minimum number of moves you need to perform to reach a safe configuration?

翻译中…

Input

翻译中…

The first line of input contains two integers $n$ and $m$ ($1 \leq n, m \leq 2000$): the number of robbers and the number of searchlight.

翻译中…

Each of the next $n$ lines contains two integers $a_i$, $b_i$ ($0 \leq a_i, b_i \leq 10^6$), coordinates of robbers.

翻译中…

Each of the next $m$ lines contains two integers $c_i$, $d_i$ ($0 \leq c_i, d_i \leq 10^6$), coordinates of searchlights.

翻译中…

Output

翻译中…

Print one integer: the minimum number of moves you need to perform to reach a safe configuration.

翻译中…

Note

翻译中…

In the first test, you can move each robber to the right three times. After that there will be one robber in the coordinates $(3, 0)$.

翻译中…

The configuration of the robbers is safe, because the only searchlight can't see the robber, because it is in the coordinates $(2, 3)$ and $3 \gt 2$.

翻译中…

In the second test, you can move each robber to the right two times and two times up. After that robbers will be in the coordinates $(3, 8)$, $(8, 3)$.

翻译中…

It's easy the see that the configuration of the robbers is safe.

翻译中…

It can be proved that you can't reach a safe configuration using no more than $3$ moves.

翻译中…

样例

Input #1
1 1
0 0
2 3
Output #1
3
InputCopy OutputCopy
Input #2
2 3
1 6
6 1
10 1
1 10
7 7
Output #2
4
InputCopy OutputCopy
Input #3
1 2
0 0
0 0
0 0
Output #3
1
InputCopy OutputCopy
Input #4
7 3
0 8
3 8
2 7
0 10
5 5
7 0
3 5
6 6
3 11
11 5
Output #4
6
InputCopy OutputCopy
题目信息
题号
1408D
所属比赛
时间限制
1 s
内存限制
256 MB
标签
二分
暴力
数据结构
动态规划
模拟
排序
双指针

题面与样例版权归 Codeforces 及出题人所有;中文翻译由 AI 生成(CI 管线),如有出入请以原文为准。