Codeforces Round 691 (Div. 2)
翻译中…
You are given two positive integer sequences $a_1, \ldots, a_n$ and $b_1, \ldots, b_m$. For each $j = 1, \ldots, m$ find the greatest common divisor of $a_1 + b_j, \ldots, a_n + b_j$.
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Input
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The first line contains two integers $n$ and $m$ ($1 \leq n, m \leq 2 \cdot 10^5$).
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The second line contains $n$ integers $a_1, \ldots, a_n$ ($1 \leq a_i \leq 10^{18})$.
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The third line contains $m$ integers $b_1, \ldots, b_m$ ($1 \leq b_j \leq 10^{18})$.
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Output
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Print $m$ integers. The $j$-th of them should be equal to GCD$(a_1 + b_j, \ldots, a_n + b_j)$.
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样例
Input #1
4 4
1 25 121 169
1 2 7 23
Output #1
2 3 8 24
InputCopy
OutputCopy
题目信息
题面与样例版权归 Codeforces 及出题人所有;中文翻译由 AI 生成(CI 管线),如有出入请以原文为准。