Codeforces Round 706 (Div. 2)
A
Split it!
Codeforces
900
原题
←B →
翻译中…

Kawashiro Nitori is a girl who loves competitive programming.

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One day she found a string and an integer. As an advanced problem setter, she quickly thought of a problem.

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Given a string $s$ and a parameter $k$, you need to check if there exist $k+1$ non-empty strings $a_1,a_2...,a_{k+1}$, such that $$s=a_1+a_2+\ldots +a_k+a_{k+1}+R(a_k)+R(a_{k-1})+\ldots+R(a_{1}).$$

翻译中…

Here $+$ represents concatenation. We define $R(x)$ as a reversed string $x$. For example $R(abcd) = dcba$. Note that in the formula above the part $R(a_{k+1})$ is intentionally skipped.

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Input

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The input consists of multiple test cases. The first line contains a single integer $t$ ($1\le t\le 100$)  — the number of test cases. The description of the test cases follows.

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The first line of each test case description contains two integers $n$, $k$ ($1\le n\le 100$, $0\le k\le \lfloor \frac{n}{2} \rfloor$)  — the length of the string $s$ and the parameter $k$.

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The second line of each test case description contains a single string $s$ of length $n$, consisting of lowercase English letters.

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Output

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For each test case, print "YES" (without quotes), if it is possible to find $a_1,a_2,\ldots,a_{k+1}$, and "NO" (without quotes) otherwise.

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You can print letters in any case (upper or lower).

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Note

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In the first test case, one possible solution is $a_1=qw$ and $a_2=q$.

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In the third test case, one possible solution is $a_1=i$ and $a_2=o$.

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In the fifth test case, one possible solution is $a_1=dokidokiliteratureclub$.

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样例

Input #1
7
5 1
qwqwq
2 1
ab
3 1
ioi
4 2
icpc
22 0
dokidokiliteratureclub
19 8
imteamshanghaialice
6 3
aaaaaa
Output #1
YES
NO
YES
NO
YES
NO
NO
InputCopy OutputCopy
题目信息
题号
1496A
时间限制
1 s
内存限制
256 MB
标签
暴力
构造
贪心
字符串

题面与样例版权归 Codeforces 及出题人所有;中文翻译由 AI 生成(CI 管线),如有出入请以原文为准。