Contest 2050 and Codeforces Round 718 (Div. 1 + Div. 2)
A
Sum of 2050
Codeforces
800
原题
←B →
翻译中…

A number is called 2050-number if it is $2050$, $20500$, ..., ($2050 \cdot 10^k$ for integer $k \ge 0$).

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Given a number $n$, you are asked to represent $n$ as the sum of some (not necessarily distinct) 2050-numbers. Compute the minimum number of 2050-numbers required for that.

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Input

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The first line contains a single integer $T$ ($1\le T\leq 1\,000$) denoting the number of test cases.

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The only line of each test case contains a single integer $n$ ($1\le n\le 10^{18}$) denoting the number to be represented.

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Output

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For each test case, output the minimum number of 2050-numbers in one line.

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If $n$ cannot be represented as the sum of 2050-numbers, output $-1$ instead.

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Note

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In the third case, $4100 = 2050 + 2050$.

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In the fifth case, $22550 = 20500 + 2050$.

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样例

Input #1
6
205
2050
4100
20500
22550
25308639900
Output #1
-1
1
2
1
2
36
InputCopy OutputCopy
题目信息
题号
1517A
时间限制
1 s
内存限制
256 MB
标签
贪心
数学

题面与样例版权归 Codeforces 及出题人所有;中文翻译由 AI 生成(CI 管线),如有出入请以原文为准。