Codeforces Round 723 (Div. 2)
B
I Hate 1111
Codeforces
1400
原题
← AC1 →
翻译中…

You are given an integer $x$. Can you make $x$ by summing up some number of $11, 111, 1111, 11111, \ldots$? (You can use any number among them any number of times).

翻译中…

For instance,

翻译中…
  • $33=11+11+11$
  • $144=111+11+11+11$
翻译中…

Input

翻译中…

The first line of input contains a single integer $t$ $(1 \leq t \leq 10000)$ — the number of testcases.

翻译中…

The first and only line of each testcase contains a single integer $x$ $(1 \leq x \leq 10^9)$ — the number you have to make.

翻译中…

Output

翻译中…

For each testcase, you should output a single string. If you can make $x$, output "YES" (without quotes). Otherwise, output "NO".

翻译中…

You can print each letter of "YES" and "NO" in any case (upper or lower).

翻译中…

Note

翻译中…

Ways to make $33$ and $144$ were presented in the statement. It can be proved that we can't present $69$ this way.

翻译中…

样例

Input #1
3
33
144
69
Output #1
YES
YES
NO
InputCopy OutputCopy
题目信息
题号
1526B
时间限制
1 s
内存限制
256 MB
标签
动态规划
数学
数论

题面与样例版权归 Codeforces 及出题人所有;中文翻译由 AI 生成(CI 管线),如有出入请以原文为准。