Given an integer $n$, find the maximum value of integer $k$ such that the following condition holds:

$n$ & ($n-1$) & ($n-2$) & ($n-3$) & ... ($k$) = $0$

where & denotes the

bitwise AND operation.

Input

The first line contains a single integer $t$ ($1 \le t \le 3 \cdot 10^4$). Then $t$ test cases follow.

The first line of each test case contains a single integer $n$ ($1 \le n \le 10^9$).

Output

For each test case, output a single integer — the required integer $k$.

Note

In the first testcase, the maximum value for which the continuous & operation gives 0 value, is 1.

In the second testcase, the maximum value for which the continuous & operation gives 0 value, is 3. No value greater then 3, say for example 4, will give the & sum 0.

• $5 \, \& \, 4 \neq 0$,
• $5 \, \& \, 4 \, \& \, 3 = 0$.

Hence, 3 is the answer.