Mocha wants to be an astrologer. There are $n$ stars which can be seen in Zhijiang, and the brightness of the $i$-th star is $a_i$.

Mocha considers that these $n$ stars form a constellation, and she uses $(a_1,a_2,\ldots,a_n)$ to show its state. A state is called mathematical if all of the following three conditions are satisfied:

• For all $i$ ($1\le i\le n$), $a_i$ is an integer in the range $[l_i, r_i]$.
• $\sum \limits _{i=1} ^ n a_i \le m$.
• $\gcd(a_1,a_2,\ldots,a_n)=1$.

Here, $\gcd(a_1,a_2,\ldots,a_n)$ denotes the greatest common divisor (GCD) of integers $a_1,a_2,\ldots,a_n$.

Mocha is wondering how many different mathematical states of this constellation exist. Because the answer may be large, you must find it modulo $998\,244\,353$.

Two states $(a_1,a_2,\ldots,a_n)$ and $(b_1,b_2,\ldots,b_n)$ are considered different if there exists $i$ ($1\le i\le n$) such that $a_i \ne b_i$.

Input

The first line contains two integers $n$ and $m$ ($2 \le n \le 50$, $1 \le m \le 10^5$) — the number of stars and the upper bound of the sum of the brightness of stars.

Each of the next $n$ lines contains two integers $l_i$ and $r_i$ ($1 \le l_i \le r_i \le m$) — the range of the brightness of the $i$-th star.

Output

Print a single integer — the number of different mathematical states of this constellation, modulo $998\,244\,353$.

Note

In the first example, there are $4$ different mathematical states of this constellation:

• $a_1=1$, $a_2=1$.
• $a_1=1$, $a_2=2$.
• $a_1=2$, $a_2=1$.
• $a_1=3$, $a_2=1$.