Codeforces Round 761 (Div. 2)
B
GCD Problem
Codeforces
900
原题
← AC →
翻译中…

Given a positive integer $n$. Find three distinct positive integers $a$, $b$, $c$ such that $a + b + c = n$ and $\operatorname{gcd}(a, b) = c$, where $\operatorname{gcd}(x, y)$ denotes the greatest common divisor (GCD) of integers $x$ and $y$.

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Input

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The input consists of multiple test cases. The first line contains a single integer $t$ ($1 \le t \le 10^5$) — the number of test cases. Description of the test cases follows.

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The first and only line of each test case contains a single integer $n$ ($10 \le n \le 10^9$).

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Output

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For each test case, output three distinct positive integers $a$, $b$, $c$ satisfying the requirements. If there are multiple solutions, you can print any. We can show that an answer always exists.

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Note

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In the first test case, $6 + 9 + 3 = 18$ and $\operatorname{gcd}(6, 9) = 3$.

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In the second test case, $21 + 39 + 3 = 63$ and $\operatorname{gcd}(21, 39) = 3$.

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In the third test case, $29 + 43 + 1 = 73$ and $\operatorname{gcd}(29, 43) = 1$.

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样例

Input #1
6
18
63
73
91
438
122690412
Output #1
6 9 3
21 39 3
29 43 1
49 35 7
146 219 73
28622 122661788 2
InputCopy OutputCopy
题目信息
题号
1617B
时间限制
2 s
内存限制
256 MB
标签
暴力
构造
数学
数论

题面与样例版权归 Codeforces 及出题人所有;中文翻译由 AI 生成(CI 管线),如有出入请以原文为准。