You are given a permutation $p$ of length $n$.

You can choose any subsequence, remove it from the permutation, and insert it at the beginning of the permutation keeping the same order.

For every $k$ from $0$ to $n$, find the minimal possible number of inversions in the permutation after you choose a subsequence of length exactly $k$.

Input

The first line contains a single integer $t$ ($1 \le t \le 50\,000$) — the number of test cases.

The first line of each test case contains one integer $n$ ($1 \le n \le 5 \cdot 10^5$) — the length of the permutation.

The second line of each test case contains the permutation $p_1, p_2, \ldots, p_n$ ($1 \le p_i \le n$).

It is guaranteed that the total sum of $n$ doesn't exceed $5 \cdot 10^5$.

Output

For each test case output $n + 1$ integers. The $i$-th of them must be the answer for the subsequence length of $i - 1$.

Note

In the second test case:

• For the length $0$: $[4, 2, 1, 3] \rightarrow [4, 2, 1, 3]$: $4$ inversions.
• For the length $1$: $[4, 2, \mathbf{1}, 3] \rightarrow [1, 4, 2, 3]$: $2$ inversions.
• For the length $2$: $[4, \mathbf{2}, \mathbf{1}, 3] \rightarrow [2, 1, 4, 3]$, or $[4, 2, \mathbf{1}, \textbf{3}] \rightarrow [1, 3, 4, 2]$: $2$ inversions.
• For the length $3$: $[4, \mathbf{2}, \mathbf{1}, \mathbf{3}] \rightarrow [2, 1, 3, 4]$: $1$ inversion.
• For the length $4$: $[\mathbf{4}, \mathbf{2}, \mathbf{1}, \mathbf{3}] \rightarrow [4, 2, 1, 3]$: $4$ inversions.