Codeforces Round 789 (Div. 2)
B2
Tokitsukaze and Good 01-String (hard version)
Codeforces
1800
原题
← B1C →
翻译中…

This is the hard version of the problem. The only difference between the two versions is that the harder version asks additionally for a minimum number of subsegments.

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Tokitsukaze has a binary string $s$ of length $n$, consisting only of zeros and ones, $n$ is even.

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Now Tokitsukaze divides $s$ into the minimum number of contiguous subsegments, and for each subsegment, all bits in each subsegment are the same. After that, $s$ is considered good if the lengths of all subsegments are even.

翻译中…

For example, if $s$ is "11001111", it will be divided into "11", "00" and "1111". Their lengths are $2$, $2$, $4$ respectively, which are all even numbers, so "11001111" is good. Another example, if $s$ is "1110011000", it will be divided into "111", "00", "11" and "000", and their lengths are $3$, $2$, $2$, $3$. Obviously, "1110011000" is not good.

翻译中…

Tokitsukaze wants to make $s$ good by changing the values of some positions in $s$. Specifically, she can perform the operation any number of times: change the value of $s_i$ to '0' or '1' ($1 \leq i \leq n$). Can you tell her the minimum number of operations to make $s$ good? Meanwhile, she also wants to know the minimum number of subsegments that $s$ can be divided into among all solutions with the minimum number of operations.

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Input

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The first contains a single positive integer $t$ ($1 \leq t \leq 10\,000$) — the number of test cases.

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For each test case, the first line contains a single integer $n$ ($2 \leq n \leq 2 \cdot 10^5$) — the length of $s$, it is guaranteed that $n$ is even.

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The second line contains a binary string $s$ of length $n$, consisting only of zeros and ones.

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It is guaranteed that the sum of $n$ over all test cases does not exceed $2 \cdot 10^5$.

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Output

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For each test case, print a single line with two integers — the minimum number of operations to make $s$ good, and the minimum number of subsegments that $s$ can be divided into among all solutions with the minimum number of operations.

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Note

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In the first test case, one of the ways to make $s$ good is the following.

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Change $s_3$, $s_6$ and $s_7$ to '0', after that $s$ becomes "1100000000", it can be divided into "11" and "00000000", which lengths are $2$ and $8$ respectively, the number of subsegments of it is $2$. There are other ways to operate $3$ times to make $s$ good, such as "1111110000", "1100001100", "1111001100", the number of subsegments of them are $2$, $4$, $4$ respectively. It's easy to find that the minimum number of subsegments among all solutions with the minimum number of operations is $2$.

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In the second, third and fourth test cases, $s$ is good initially, so no operation is required.

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样例

Input #1
5
10
1110011000
8
11001111
2
00
2
11
6
100110
Output #1
3 2
0 3
0 1
0 1
3 1
InputCopy OutputCopy
题目信息
题号
1678B2
时间限制
1 s
内存限制
256 MB
标签
动态规划
贪心
模拟

题面与样例版权归 Codeforces 及出题人所有;中文翻译由 AI 生成(CI 管线),如有出入请以原文为准。