As she closed the Satori's eye that could read minds, Koishi gained the ability to live in unconsciousness. Even she herself does not know what she is up to.— Subterranean Animism
Koishi is unconsciously permuting $n$ numbers: $1, 2, \ldots, n$.
She thinks the permutation $p$ is beautiful if $s=\sum\limits_{i=1}^{n-1} [p_i+1=p_{i+1}]$. $[x]$ equals to $1$ if $x$ holds, or $0$ otherwise.
For each $k\in[0,n-1]$, she wants to know the number of beautiful permutations of length $n$ satisfying $k=\sum\limits_{i=1}^{n-1}[p_i \lt p_{i+1}]$.
Input
There is one line containing two intergers $n$ ($1 \leq n \leq 250\,000$) and $s$ ($0 \leq s \lt n$).
Output
Print one line with $n$ intergers. The $i$-th integers represents the answer of $k=i-1$, modulo $998244353$.
Note
Let $f(p)=\sum\limits_{i=1}^{n-1}[p_i \lt p_{i+1}]$.
Testcase 1:
$[2,1]$ is the only beautiful permutation. And $f([2,1])=0$.
Testcase 2:
Beautiful permutations:
$[1,2,4,3]$, $[1,3,4,2]$, $[1,4,2,3]$, $[2,1,3,4]$, $[2,3,1,4]$, $[3,1,2,4]$, $[3,4,2,1]$, $[4,2,3,1]$, $[4,3,1,2]$. The first six of them satisfy $f(p)=2$, while others satisfy $f(p)=1$.
样例
2 0
1 0
4 1
0 3 6 0
8 3
0 0 0 35 770 980 70 0
题面与样例版权归 Codeforces 及出题人所有;中文翻译由 AI 生成(CI 管线),如有出入请以原文为准。