Codeforces Round 801 (Div. 2) and EPIC Institute of Technology Round
D1
Tree Queries (Easy Version)
Codeforces
2200
原题
← CD2 →
翻译中…

The only difference between this problem and D2 is the bound on the size of the tree.

翻译中…

You are given an unrooted tree with $n$ vertices. There is some hidden vertex $x$ in that tree that you are trying to find.

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To do this, you may ask $k$ queries $v_1, v_2, \ldots, v_k$ where the $v_i$ are vertices in the tree. After you are finished asking all of the queries, you are given $k$ numbers $d_1, d_2, \ldots, d_k$, where $d_i$ is the number of edges on the shortest path between $v_i$ and $x$. Note that you know which distance corresponds to which query.

翻译中…

What is the minimum $k$ such that there exists some queries $v_1, v_2, \ldots, v_k$ that let you always uniquely identify $x$ (no matter what $x$ is).

翻译中…

Note that you don't actually need to output these queries.

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Input

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Each test contains multiple test cases. The first line contains the number of test cases $t$ ($1 \le t \le 100$). Description of the test cases follows.

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The first line of each test case contains a single integer $n$ ($1 \le n \le 2000$)  — the number of vertices in the tree.

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Each of the next $n-1$ lines contains two integers $x$ and $y$ ($1 \le x, y \le n$), meaning there is an edges between vertices $x$ and $y$ in the tree.

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It is guaranteed that the given edges form a tree.

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It is guaranteed that the sum of $n$ over all test cases does not exceed $2000$.

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Output

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For each test case print a single nonnegative integer, the minimum number of queries you need, on its own line.

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Note

翻译中…

In the first test case, there is only one vertex, so you don't need any queries.

翻译中…

In the second test case, you can ask a single query about the node $1$. Then, if $x = 1$, you will get $0$, otherwise you will get $1$.

翻译中…

样例

Input #1
3
1
2
1 2
10
2 4
2 1
5 7
3 10
8 6
6 1
1 3
4 7
9 6
Output #1
0
1
2
InputCopy OutputCopy
题目信息
题号
1695D1
时间限制
2 s
内存限制
256 MB
标签
暴力
构造
DFS 及类似
动态规划
贪心
树

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