This is the easy version of the problem. The only difference between the versions is the constraints on $n$, $k$, $a_i$, and the sum of $n$ over all test cases. You can make hacks only if both versions of the problem are solved.

Note the unusual memory limit.

You are given an array of integers $a_1, a_2, \ldots, a_n$ of length $n$, and an integer $k$.

The cost of an array of integers $p_1, p_2, \ldots, p_n$ of length $n$ is $$\max\limits_{1 \le i \le n}\left(\left \lfloor \frac{a_i}{p_i} \right \rfloor \right) - \min\limits_{1 \le i \le n}\left(\left \lfloor \frac{a_i}{p_i} \right \rfloor \right).$$

Here, $\lfloor \frac{x}{y} \rfloor$ denotes the integer part of the division of $x$ by $y$. Find the minimum cost of an array $p$ such that $1 \le p_i \le k$ for all $1 \le i \le n$.

Input

The first line contains a single integer $t$ ($1 \le t \le 100$) — the number of test cases.

The first line of each test case contains two integers $n$ and $k$ ($1 \le n, k \le 3000$).

The second line contains $n$ integers $a_1, a_2, \ldots, a_n$ ($1 \le a_1 \le a_2 \le \ldots \le a_n \le 3000$).

It is guaranteed that the sum of $n$ over all test cases does not exceed $3000$.

Output

For each test case, print a single integer — the minimum possible cost of an array $p$ satisfying the condition above.

Note

In the first test case, the optimal array is $p = [1, 1, 1, 2, 2]$. The resulting array of values of $\lfloor \frac{a_i}{p_i} \rfloor$ is $[4, 5, 6, 4, 5]$. The cost of $p$ is $\max\limits_{1 \le i \le n}(\lfloor \frac{a_i}{p_i} \rfloor) - \min\limits_{1 \le i \le n}(\lfloor \frac{a_i}{p_i} \rfloor) = 6 - 4 = 2$. We can show that there is no array (satisfying the condition from the statement) with a smaller cost.

In the second test case, one of the optimal arrays is $p = [12, 12, 12, 12, 12]$, which results in all $\lfloor \frac{a_i}{p_i} \rfloor$ being $0$.

In the third test case, the only possible array is $p = [1, 1, 1]$.