I wonder, does the falling rain

*Forever yearn for it's disdain?*Effluvium of the Mind

You are given a positive integer $n$.

Find any permutation $p$ of length $n$ such that the sum $\operatorname{lcm}(1,p_1) + \operatorname{lcm}(2, p_2) + \ldots + \operatorname{lcm}(n, p_n)$ is as large as possible.

Here $\operatorname{lcm}(x, y)$ denotes the least common multiple (LCM) of integers $x$ and $y$.

A permutation is an array consisting of $n$ distinct integers from $1$ to $n$ in arbitrary order. For example, $[2,3,1,5,4]$ is a permutation, but $[1,2,2]$ is not a permutation ($2$ appears twice in the array) and $[1,3,4]$ is also not a permutation ($n=3$ but there is $4$ in the array).

Input

Each test contains multiple test cases. The first line contains the number of test cases $t$ ($1 \le t \le 1\,000$). Description of the test cases follows.

The only line for each test case contains a single integer $n$ ($1 \le n \le 10^5$).

It is guaranteed that the sum of $n$ over all test cases does not exceed $10^5$.

Output

For each test case print $n$ integers $p_1$, $p_2$, $\ldots$, $p_n$ — the permutation with the maximum possible value of $\operatorname{lcm}(1,p_1) + \operatorname{lcm}(2, p_2) + \ldots + \operatorname{lcm}(n, p_n)$.

If there are multiple answers, print any of them.

Note

For $n = 1$, there is only one permutation, so the answer is $[1]$.

For $n = 2$, there are two permutations:

• $[1, 2]$ — the sum is $\operatorname{lcm}(1,1) + \operatorname{lcm}(2, 2) = 1 + 2 = 3$.
• $[2, 1]$ — the sum is $\operatorname{lcm}(1,2) + \operatorname{lcm}(2, 1) = 2 + 2 = 4$.