Croc Champ 2012 - Qualification Round
E
BHTML+BCSS
Codeforces
2200
原题
← D→
翻译中…

This problem is about imaginary languages BHTML and BCSS, which slightly resemble HTML and CSS. Read the problem statement carefully as the resemblance is rather slight and the problem uses very simplified analogs.

翻译中…

You are given a BHTML document that resembles HTML but is much simpler. It is recorded as a sequence of opening and closing tags. A tag that looks like "<tagname>" is called an opening tag and a tag that looks like "</tagname>" is called a closing tag. Besides, there are self-closing tags that are written as "<tagname/>" and in this problem they are fully equivalent to "<tagname></tagname>". All tagnames in this problem are strings consisting of lowercase Latin letters with length from 1 to 10 characters. Tagnames of different tags may coincide.

翻译中…

The document tags form a correct bracket sequence, that is, we can obtain an empty sequence from the given one using the following operations:

翻译中…
  • remove any self-closing tag "<tagname/>",
  • remove a pair of an opening and a closing tag that go consecutively (in this order) and have the same names. In other words, remove substring "<tagname></tagname>".
翻译中…

For example, you may be given such document: "<header><p><a/><b></b></p></header><footer></footer>" but you may not be given documents "<a>", "<a></b>", "</a><a>" or "<a><b></a></b>".

翻译中…

Obviously, for any opening tag there is the only matching closing one — each such pair is called an element. A self-closing tag also is an element. Let's consider that one element is nested inside another one, if tags of the first element are between tags of the second one. An element is not nested to itself. For instance, in the example above element "b" is nested in "header" and in "p", but it isn't nested in "a" and "footer", also it isn't nested to itself ("b"). Element "header" has three elements nested in it, and "footer" has zero.

翻译中…

We need the BCSS rules to apply styles when displaying elements of the BHTML documents. Each rule is recorded as a subsequence of words "x1 x2 ... xn". This rule has effect over all such elements $*t*$, which satisfy both conditions from the list:

翻译中…
  • there is a sequence of nested elements with tagnames "x1", "x2", ..., "xn" (that is, the second element is nested in the first one, the third element is nested in the second one and so on),
  • this sequence ends with element $*t*$ (i.e. tagname of element $*t*$ equals "xn").
翻译中…

For example, element "b" meets the conditions of the rule "a b" if for element "b" exists element "a" in which it is nested. Element "c" meets the conditions of the rule "a b b c", if three elements exist: "a", "b", "b", and in the chain "a"-"b"-"b"-"c" each following element is nested in the previous one.

翻译中…

Given a BHTML document and a set of BCSS rules, write a program that determines the number of elements that meet the conditions of each rule.

翻译中…

Input

翻译中…

The first line of the input contains a BHTML-document. The document has length from $4$ to $10^{6}$ characters. The document has a correct structure, doesn't contain spaces or any other unnecessary characters. Tagnames consist of lowercase Latin letters, their lengths are from 1 to 10 characters.

翻译中…

The second line contains an integer $*m*$ ($1 ≤ *m* ≤ 200$) — the number of queries. Then $*m*$ lines contain the queries, one per line. Each query is a sequence $*x*_{1}, *x*_{2}, ..., *x*_{*n*}$, where $*x*_{*i*}$ is the $*i*$-th element of the query, and $*n*$ ($1 ≤ *n* ≤ 200$) is the number of elements in the query. The elements are separated by single spaces. Each query doesn't begin with and doesn't end with a space. Each query element is a sequence of lowercase Latin letters with length from 1 to 10.

翻译中…

Output

翻译中…

Print $*m*$ lines, the $*j*$-th line should contain the number of elements of the document that correspond to the $*j*$-th BCSS-rule. If there are no such elements at all, print on the line 0.

翻译中…

样例

Input #1
<a><b><b></b></b></a><a><b></b><b><v/></b></a><b></b>
4
a
a b b
a b
b a
Output #1
2
1
4
0
InputCopy OutputCopy
Input #2
<b><aa/></b><aa><b/><b/></aa>
5
aa b
b
aa
b aa
a
Output #2
2
3
2
1
0
InputCopy OutputCopy
题目信息
题号
172E
时间限制
4 s
内存限制
256 MB
标签
*special
DFS 及类似
表达式解析

题面与样例版权归 Codeforces 及出题人所有;中文翻译由 AI 生成(CI 管线),如有出入请以原文为准。