Nikephoros and Polycarpus play rock-paper-scissors. The loser gets pinched (not too severely!).

Let us remind you the rules of this game. Rock-paper-scissors is played by two players. In each round the players choose one of three items independently from each other. They show the items with their hands: a rock, scissors or paper. The winner is determined by the following rules: the rock beats the scissors, the scissors beat the paper and the paper beats the rock. If the players choose the same item, the round finishes with a draw.

Nikephoros and Polycarpus have played $*n*$ rounds. In each round the winner gave the loser a friendly pinch and the loser ended up with a fresh and new red spot on his body. If the round finished in a draw, the players did nothing and just played on.

Nikephoros turned out to have worked out the following strategy: before the game began, he chose some sequence of items $*A* = (*a*_{1}, *a*_{2}, ..., *a*_{*m*})$, and then he cyclically showed the items from this sequence, starting from the first one. Cyclically means that Nikephoros shows signs in the following order: $*a*_{1}$, $*a*_{2}$, $...$, $*a*_{*m*}$, $*a*_{1}$, $*a*_{2}$, $...$, $*a*_{*m*}$, $*a*_{1}$, $...$ and so on. Polycarpus had a similar strategy, only he had his own sequence of items $*B* = (*b*_{1}, *b*_{2}, ..., *b*_{*k*})$.

Determine the number of red spots on both players after they've played $*n*$ rounds of the game. You can consider that when the game began, the boys had no red spots on them.

Input

The first line contains integer $*n*$ ($1 ≤ *n* ≤ 2·10^{9}$) — the number of the game's rounds.

The second line contains sequence $*A*$ as a string of $*m*$ characters and the third line contains sequence $*B*$ as a string of $*k*$ characters ($1 ≤ *m*, *k* ≤ 1000$). The given lines only contain characters "R", "S" and "P". Character "R" stands for the rock, character "S" represents the scissors and "P" represents the paper.

Output

Print two space-separated integers: the numbers of red spots Nikephoros and Polycarpus have.

Note

In the first sample the game went like this:

• R - R. Draw.
• P - S. Nikephoros loses.
• S - P. Polycarpus loses.
• R - P. Nikephoros loses.
• P - R. Polycarpus loses.
• S - S. Draw.
• R - P. Nikephoros loses.

Thus, in total Nikephoros has $3$ losses (and $3$ red spots), and Polycarpus only has $2$.