Codeforces Round 858 (Div. 2)
A
Walking Master
Codeforces
800
原题
←B →
翻译中…

YunQian is standing on an infinite plane with the Cartesian coordinate system on it. In one move, she can move to the diagonally adjacent point on the top right or the adjacent point on the left.

翻译中…

That is, if she is standing on point $(x,y)$, she can either move to point $(x+1,y+1)$ or point $(x-1,y)$.

翻译中…

YunQian initially stands at point $(a,b)$ and wants to move to point $(c,d)$. Find the minimum number of moves she needs to make or declare that it is impossible.

翻译中…

Input

翻译中…

The first line contains a single integer $t$ ($1\le t\le 10^4$) — the number of test cases. The description of test cases follows.

翻译中…

The first line and only line of each test case contain four integers $a$, $b$, $c$, $d$ ($-10^8\le a,b,c,d\le 10^8$).

翻译中…

Output

翻译中…

For each test case, if it is possible to move from point $(a,b)$ to point $(c,d)$, output the minimum number of moves. Otherwise, output $-1$.

翻译中…

Note

翻译中…

In the first test case, one possible way using $4$ moves is $(-1,0)\to (0,1)\to (-1,1)\to (0,2)\to (-1,2)$. It can be proven that it is impossible to move from point $(-1,0)$ to point $(-1,2)$ in less than $4$ moves.

翻译中…

样例

Input #1
6
-1 0 -1 2
0 0 4 5
-2 -1 1 1
-3 2 -3 2
2 -1 -1 -1
1 1 0 2
Output #1
4
6
-1
0
3
3
InputCopy OutputCopy
题目信息
题号
1806A
时间限制
1 s
内存限制
1024 MB
标签
计算几何
贪心
数学

题面与样例版权归 Codeforces 及出题人所有;中文翻译由 AI 生成(CI 管线),如有出入请以原文为准。