Codeforces Round 869 (Div. 2)
B
Indivisible
Codeforces
900
原题
← AC →
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You're given a positive integer $n$.

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Find a permutation $a_1, a_2, \dots, a_n$ such that for any $1 \leq l \lt r \leq n$, the sum $a_l + a_{l+1} + \dots + a_r$ is not divisible by $r-l+1$.

翻译中…

A permutation of length $n$ is an array consisting of $n$ distinct integers from $1$ to $n$ in arbitrary order. For example, $[2,3,1,5,4]$ is a permutation, but $[1,2,2]$ is not a permutation ($2$ appears twice in the array), and $[1,3,4]$ is also not a permutation ($n=3$ but there is $4$ in the array).

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Input

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Each test contains multiple test cases. The first line contains the number of test cases $t$ ($1 \le t \le 100$). Description of the test cases follows.

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The first line of each test case contain a single integer $n$ ($1 \leq n \leq 100$) — the size of the desired permutation.

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Output

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For each test case, if there is no such permutation print $-1$.

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Otherwise, print $n$ distinct integers $p_1, p_{2}, \dots, p_n$ ($1 \leq p_i \leq n$) — a permutation satisfying the condition described in the statement.

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If there are multiple solutions, print any.

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Note

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In the first example, there are no valid pairs of $l \lt r$, meaning that the condition is true for all such pairs.

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In the second example, the only valid pair is $l=1$ and $r=2$, for which $a_1 + a_2 = 1+2=3$ is not divisible by $r-l+1=2$.

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in the third example, for $l=1$ and $r=3$ the sum $a_1+a_2+a_3$ is always $6$, which is divisible by $3$.

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样例

Input #1
3
1
2
3
Output #1
1
1 2
-1
InputCopy OutputCopy
题目信息
题号
1818B
时间限制
1 s
内存限制
256 MB
标签
构造

题面与样例版权归 Codeforces 及出题人所有;中文翻译由 AI 生成(CI 管线),如有出入请以原文为准。