Ntarsis has an array $a$ of length $n$.
The power of a subarray $a_l \dots a_r$ ($1 \leq l \leq r \leq n$) is defined as:
- The largest value
$x$such that$a_l \dots a_r$contains$x$and neither$a_1 \dots a_{l-1}$nor$a_{r+1} \dots a_n$contains$x$. - If no such
$x$exists, the power is$0$.
Call an array $b$ a rival to $a$ if the following holds:
- The length of both
$a$and$b$are equal to some$n$. - Over all
$l, r$where$1 \leq l \leq r \leq n$, the power of$a_l \dots a_r$equals the power of$b_l \dots b_r$. - The elements of
$b$are positive.
Ntarsis wants you to find a rival $b$ to $a$ such that the sum of $b_i$ over $1 \leq i \leq n$ is maximized. Help him with this task!
Input
Each test contains multiple test cases. The first line contains the number of test cases $t$ ($1 \le t \le 10^5$). The description of the test cases follows.
The first line of each test case has a single integer $n$ ($1 \leq n \leq 10^5$).
The next line contains $n$ integers $a_1, a_2, \ldots, a_n$ ($1 \leq a_i \leq 10^9$).
It is guaranteed that the sum of $n$ across all test cases does not exceed $2 \cdot 10^5$.
Output
For each test case, output $n$ integers $b_1, b_2, \ldots, b_n$ — a valid rival to $a$ such that $b_1 + b_2 + \cdots + b_n$ is maximal.
If there exist multiple rivals with the maximum sum, output any of them.
Note
For the first test case, one rival with the maximal sum is $[2, 4, 2, 3, 3]$.
$[2, 4, 2, 3, 3]$ can be shown to be a rival to $[1, 4, 1, 3, 3]$.
All possible subarrays of $a$ and $b$ and their corresponding powers are listed below:
- The power of
$a[1:1] = [1] = 0$, the power of$b[1:1] = [2] = 0$. - The power of
$a[1:2] = [1, 4] = 4$, the power of$b[1:2] = [2, 4] = 4$. - The power of
$a[1:3] = [1, 4, 1] = 4$, the power of$b[1:3] = [2, 4, 2] = 4$. - The power of
$a[1:4] = [1, 4, 1, 3] = 4$, the power of$b[1:4] = [2, 4, 2, 3] = 4$. - The power of
$a[1:5] = [1, 4, 1, 3, 3] = 4$, the power of$b[1:5] = [2, 4, 2, 3, 3] = 4$. - The power of
$a[2:2] = [4] = 4$, the power of$b[2:2] = [4] = 4$. - The power of
$a[2:3] = [4, 1] = 4$, the power of$b[2:3] = [4, 2] = 4$. - The power of
$a[2:4] = [4, 1, 3] = 4$, the power of$b[2:4] = [4, 2, 3] = 4$. - The power of
$a[2:5] = [4, 1, 3, 3] = 4$, the power of$b[2:5] = [4, 2, 3, 3] = 4$. - The power of
$a[3:3] = [1] = 0$, the power of$b[3:3] = [2] = 0$. - The power of
$a[3:4] = [1, 3] = 0$, the power of$b[3:4] = [2, 3] = 0$. - The power of
$a[3:5] = [1, 3, 3] = 3$, the power of$b[3:5] = [2, 3, 3] = 3$. - The power of
$a[4:4] = [3] = 0$, the power of$b[4:4] = [3] = 0$. - The power of
$a[4:5] = [3, 3] = 3$, the power of$b[4:5] = [3, 3] = 3$. - The power of
$a[5:5] = [3] = 0$, the power of$b[5:5] = [3] = 0$.
It can be shown there exists no rival with a greater sum than $2 + 4 + 2 + 3 + 3 = 14$.
样例
7
5
1 4 1 3 3
5
1 4 1 8 8
5
2 1 1 1 2
8
3 2 3 5 2 2 5 3
8
1 1 1 1 4 3 3 3
10
1 9 5 9 8 1 5 8 9 1
16
1 1 1 1 5 5 5 5 9 9 9 9 7 7 7 7
2 4 2 3 3
3 4 3 8 8
2 1 2 1 2
4 2 4 5 5 2 5 4
1 2 2 1 4 3 2 3
7 9 5 9 8 9 5 8 9 7
1 8 8 1 5 8 8 5 9 9 9 9 7 8 8 7
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