Codeforces Round 892 (Div. 2)
C
Another Permutation Problem
Codeforces
1200
原题
← BD →
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Andrey is just starting to come up with problems, and it's difficult for him. That's why he came up with a strange problem about permutations$^{\dagger}$ and asks you to solve it. Can you do it?

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Let's call the cost of a permutation $p$ of length $n$ the value of the expression:

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$(\sum_{i = 1}^{n} p_i \cdot i) - (\max_{j = 1}^{n} p_j \cdot j)$.

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Find the maximum cost among all permutations of length $n$.

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$^{\dagger}$A permutation of length $n$ is an array consisting of $n$ distinct integers from $1$ to $n$ in arbitrary order. For example, $[2,3,1,5,4]$ is a permutation, but $[1,2,2]$ is not a permutation ($2$ appears twice in the array), and $[1,3,4]$ is also not a permutation ($n=3$ but there is $4$ in the array).

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Input

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Each test consists of multiple test cases. The first line contains a single integer $t$ ($1 \le t \le 30$) — the number of test cases. The description of the test cases follows.

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The only line of each test case contains a single integer $n$ ($2 \le n \le 250$) — the length of the permutation.

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It is guaranteed that the sum of $n$ over all test cases does not exceed $500$.

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Output

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For each test case, output a single integer — the maximum cost among all permutations of length $n$.

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Note

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In the first test case, the permutation with the maximum cost is $[2, 1]$. The cost is equal to $2 \cdot 1 + 1 \cdot 2 - \max (2 \cdot 1, 1 \cdot 2)= 2 + 2 - 2 = 2$.

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In the second test case, the permutation with the maximum cost is $[1, 2, 4, 3]$. The cost is equal to $1 \cdot 1 + 2 \cdot 2 + 4 \cdot 3 + 3 \cdot 4 - 4 \cdot 3 = 17$.

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样例

Input #1
5
2
4
3
10
20
Output #1
2
17
7
303
2529
InputCopy OutputCopy
题目信息
题号
1859C
时间限制
3 s
内存限制
256 MB
标签
暴力
动态规划
贪心
数学

题面与样例版权归 Codeforces 及出题人所有;中文翻译由 AI 生成(CI 管线),如有出入请以原文为准。