Pinely Round 2 (Div. 1 + Div. 2)
C
MEX Repetition
Codeforces
1100
原题
← BD →
翻译中…

You are given an array $a_1,a_2,\ldots, a_n$ of pairwise distinct integers from $0$ to $n$. Consider the following operation:

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  • consecutively for each $i$ from $1$ to $n$ in this order, replace $a_i$ with $\operatorname{MEX}(a_1, a_2, \ldots, a_n)$.
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Here $\operatorname{MEX}$ of a collection of integers $c_1, c_2, \ldots, c_m$ is defined as the smallest non-negative integer $x$ which does not occur in the collection $c$. For example, $\operatorname{MEX}(0, 2, 2, 1, 4) = 3$ and $\operatorname{MEX}(1, 2) = 0$.

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Print the array after applying $k$ such operations.

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Input

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Each test contains multiple test cases. The first line contains the number of test cases $t$ ($1 \le t \le 10^5$). The description of the test cases follows.

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The first line of each test case contains two integers $n$ and $k$ ($1\le n\le 10^5$, $1\le k\le 10^9$).

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The second line contains $n$ pairwise distinct integers $a_1,a_2,\ldots, a_n$ ($0\le a_i\le n$) representing the elements of the array before applying the operations.

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It is guaranteed that the sum of $n$ over all test cases does not exceed $10^5$.

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Output

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For each test case, print all $n$ elements of the array after applying $k$ operations.

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Note

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In the first test case, here is the entire process:

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  1. On the first operation, the array changes from $[1]$ to $[0]$, since $\operatorname{MEX}(1) = 0$.
  2. On the second operation, the array changes from $[0]$ to $[1]$, since $\operatorname{MEX}(0) = 1$.
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Thus, the array becomes $[1]$ after two operations.

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In the second test case, the array changes as follows during one operation: $[{\mkern3mu\underline{\mkern-3mu {\bf 0}\mkern-3mu}\mkern3mu}, 1, 3] \rightarrow [2, {\mkern3mu\underline{\mkern-3mu {\bf 1}\mkern-3mu}\mkern3mu}, 3] \rightarrow [2, 0, {\mkern3mu\underline{\mkern-3mu {\bf 3}\mkern-3mu}\mkern3mu}] \rightarrow [2, 0, 1]$.

翻译中…

In the third test case, the array changes as follows during one operation: $[{\mkern3mu\underline{\mkern-3mu {\bf 0}\mkern-3mu}\mkern3mu}, 2] \rightarrow [1, {\mkern3mu\underline{\mkern-3mu {\bf 2}\mkern-3mu}\mkern3mu}] \rightarrow [1, 0]$. And during the second operation: $[{\mkern3mu\underline{\mkern-3mu {\bf 1}\mkern-3mu}\mkern3mu}, 0] \rightarrow [2, {\mkern3mu\underline{\mkern-3mu {\bf 0}\mkern-3mu}\mkern3mu}] \rightarrow [2, 1]$.

翻译中…

样例

Input #1
5
1 2
1
3 1
0 1 3
2 2
0 2
5 5
1 2 3 4 5
10 100
5 3 0 4 2 1 6 9 10 8
Output #1
1
2 0 1
2 1
2 3 4 5 0
7 5 3 0 4 2 1 6 9 10
InputCopy OutputCopy
题目信息
题号
1863C
时间限制
2 s
内存限制
256 MB
标签
模拟
数学

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