Entering senior high school life, Tom is attracted by LIS problems, not only the Longest Increasing Subsequence problem, but also the Largest Interval Sum problem. Now he gets a really interesting problem from his friend Daniel. However, it seems too hard for him to solve it, so he asks you for help.

Given an array $a$ consisting of $n$ integers.

In one operation, you do the following:

• Select an interval $[l,r]$ ($1\le l\le r\le n$), such that the sum of the interval is the largest among all intervals in the array $a$. More formally, $\displaystyle\sum_{i=l}^r a_i=\max_{1\le l'\le r'\le n}\sum_{i=l'}^{r'} a_i$.
• Then subtract $1$ from all elements $a_l,a_{l+1},\ldots,a_r$.

Find the minimum number of operations you need to perform to make $a_i \lt 0$ for every $1\le i\le n$.

Input

The first line of input contains a single integer $n$ ($1 \le n \le 5 \cdot 10^5$) — the length of the array $a$.

The second line contains $n$ integers $a_1,a_2,\ldots,a_n$ ($-10^6\le a_i\le 10^6$) — the elements of the array $a$.

Output

Print a single integer — the minimum number of operations.

Note

In the first example, you can do operations on intervals $[1,5],[1,5],[2,5],[3,5],[4,5],[5,5]$ in such order. You may also do operations on intervals $[1,5],[2,5],[3,5],[4,5],[5,5],[1,5]$ in such order.

In the second example, it's already satisfied that $a_i \lt 0$ for every $1\le i\le n$. So you do not need to perform any operations.