You have $n$ stacks $r_1,r_2,\ldots,r_n$. Each stack contains some positive integers ranging from $1$ to $n$.
Define the following functions:
function init(pos):
stacks := an array that contains n stacks r[1], r[2], ..., r[n]
return get(stacks, pos)
function get(stacks, pos):
if stacks[pos] is empty:
return pos
else:
new_pos := the top element of stacks[pos]
pop the top element of stacks[pos]
return get(stacks, new_pos)
You want to know the values returned by $\texttt{init(1)}, \texttt{init(2)}, \ldots, \texttt{init(n)}$.
Note that, during these calls, the stacks $r_1,r_2,\ldots,r_n$ don't change, so the calls $\texttt{init(1)}, \texttt{init(2)}, \ldots, \texttt{init(n)}$ are independent.
Input
The first line of the input contains one integer $n$ ($1\le n\le 10^5$) — the length of the array $r$.
Each of the following $n$ lines contains several integers. The first integer $k_i$ ($0\le k_i\le 10^5$) represents the number of elements in the $i$-th stack, and the following $k_i$ positive integers $c_{i,1},c_{i,2},\ldots,c_{i,k_i}$ ($1\le c_{i,j}\le n$) represent the elements in the $i$-th stack. $c_{i,1}$ is the bottom element.
In each test, $\sum k_i\le 10^6$.
Output
You need to output $n$ values, the $i$-th of which is the value returned by $\texttt{init(i)}$.
Note
In the first example:
- When you call
$\texttt{init(1)}$, set$\texttt{stacks := [[1,2,2],[3,1,2],[1,2,1]]}$, and then call$\texttt{get(stacks, 1)}$. $\texttt{stacks[1]}$is not empty, set$\texttt{new_pos := 2}$, and pop the top element of$\texttt{stacks[1]}$, which makes$\texttt{stacks}$become$[[1,2],[3,1,2],[1,2,1]]$, and then call$\texttt{get(stacks, 2)}$.$\texttt{stacks[2]}$is not empty, set$\texttt{new_pos := 2}$, and pop the top element of$\texttt{stacks[2]}$, which makes$\texttt{stacks}$become$[[1,2],[3,1],[1,2,1]]$, and then call$\texttt{get(stacks, 2)}$.$\texttt{stacks[2]}$is not empty, set$\texttt{new_pos := 1}$, and pop the top element of$\texttt{stacks[2]}$, which makes$\texttt{stacks}$become$[[1,2],[3],[1,2,1]]$, and then call$\texttt{get(stacks, 1)}$.$\texttt{stacks[1]}$is not empty, set$\texttt{new_pos := 2}$, and pop the top element of$\texttt{stacks[1]}$, which makes$\texttt{stacks}$become$[[1],[3],[1,2,1]]$, and then call$\texttt{get(stacks, 2)}$.$\texttt{stacks[2]}$is not empty, set$\texttt{new_pos := 3}$, and pop the top element of$\texttt{stacks[2]}$, which makes$\texttt{stacks}$become$[[1],[],[1,2,1]]$, and then call$\texttt{get(stacks, 3)}$.$\texttt{stacks[3]}$is not empty, set$\texttt{new_pos := 1}$, and pop the top element of$\texttt{stacks[3]}$, which makes$\texttt{stacks}$become$[[1],[],[1,2]]$, and then call$\texttt{get(stacks, 1)}$.$\texttt{stacks[1]}$is not empty, set$\texttt{new_pos := 1}$, and pop the top element of$\texttt{stacks[1]}$, which makes$\texttt{stacks}$become$[[],[],[1,2]]$, and then call$\texttt{get(stacks, 1)}$.$\texttt{stacks[1]}$is empty, return$1$.
- When you call
$\texttt{init(2)}$, set$\texttt{stacks := [[1,2,2],[3,1,2],[1,2,1]]}$, and then call$\texttt{get(stacks, 2)}$. $\texttt{stacks[2]}$is not empty, set$\texttt{new_pos := 2}$, and pop the top element of$\texttt{stacks[2]}$, which makes$\texttt{stacks}$become$[[1,2,2],[3,1],[1,2,1]]$, and then call$\texttt{get(stacks, 2)}$.$\texttt{stacks[2]}$is not empty, set$\texttt{new_pos := 1}$, and pop the top element of$\texttt{stacks[2]}$, which makes$\texttt{stacks}$become$[[1,2,2],[3],[1,2,1]]$, and then call$\texttt{get(stacks, 1)}$.$\texttt{stacks[1]}$is not empty, set$\texttt{new_pos := 2}$, and pop the top element of$\texttt{stacks[1]}$, which makes$\texttt{stacks}$become$[[1,2],[3],[1,2,1]]$, and then call$\texttt{get(stacks, 2)}$.$\texttt{stacks[2]}$is not empty, set$\texttt{new_pos := 3}$, and pop the top element of$\texttt{stacks[2]}$, which makes$\texttt{stacks}$become$[[1,2],[],[1,2,1]]$, and then call$\texttt{get(stacks, 3)}$.$\texttt{stacks[3]}$is not empty, set$\texttt{new_pos := 1}$, and pop the top element of$\texttt{stacks[3]}$, which makes$\texttt{stacks}$become$[[1,2],[],[1,2]]$, and then call$\texttt{get(stacks, 1)}$.$\texttt{stacks[1]}$is not empty, set$\texttt{new_pos := 2}$, and pop the top element of$\texttt{stacks[1]}$, which makes$\texttt{stacks}$become$[[1],[],[1,2]]$, and then call$\texttt{get(stacks, 2)}$.$\texttt{stacks[2]}$is empty, return$2$.
- When you call
$\texttt{init(3)}$, set$\texttt{stacks := [[1,2,2],[3,1,2],[1,2,1]]}$, and then call$\texttt{get(stacks, 3)}$. $\texttt{stacks[3]}$is not empty, set$\texttt{new_pos := 1}$, and pop the top element of$\texttt{stacks[3]}$, which makes$\texttt{stacks}$become$[[1,2,2],[3,1,2],[1,2]]$, and then call$\texttt{get(stacks, 1)}$.$\texttt{stacks[1]}$is not empty, set$\texttt{new_pos := 2}$, and pop the top element of$\texttt{stacks[1]}$, which makes$\texttt{stacks}$become$[[1,2],[3,1,2],[1,2]]$, and then call$\texttt{get(stacks, 2)}$.$\texttt{stacks[2]}$is not empty, set$\texttt{new_pos := 2}$, and pop the top element of$\texttt{stacks[2]}$, which makes$\texttt{stacks}$become$[[1,2],[3,1],[1,2]]$, and then call$\texttt{get(stacks, 2)}$.$\texttt{stacks[2]}$is not empty, set$\texttt{new_pos := 1}$, and pop the top element of$\texttt{stacks[2]}$, which makes$\texttt{stacks}$become$[[1,2],[3],[1,2]]$, and then call$\texttt{get(stacks, 1)}$.$\texttt{stacks[1]}$is not empty, set$\texttt{new_pos := 2}$, and pop the top element of$\texttt{stacks[1]}$, which makes$\texttt{stacks}$become$[[1],[3],[1,2]]$, and then call$\texttt{get(stacks, 2)}$.$\texttt{stacks[2]}$is not empty, set$\texttt{new_pos := 3}$, and pop the top element of$\texttt{stacks[2]}$, which makes$\texttt{stacks}$become$[[1],[],[1,2]]$, and then call$\texttt{get(stacks, 3)}$.$\texttt{stacks[3]}$is not empty, set$\texttt{new_pos := 2}$, and pop the top element of$\texttt{stacks[3]}$, which makes$\texttt{stacks}$become$[[1],[],[1]]$, and then call$\texttt{get(stacks, 2)}$.$\texttt{stacks[2]}$is empty, return$2$.
样例
3
3 1 2 2
3 3 1 2
3 1 2 1
1 2 2
5
5 1 2 4 3 4
6 1 2 5 3 3 4
6 1 1 4 4 4 2
9 3 1 4 2 3 5 5 1 2
4 4 4 1 3
1 1 1 1 1
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