Codeforces Round 931 (Div. 2)
A
Too Min Too Max
Codeforces
800
原题
←B →
翻译中…

Given an array $a$ of $n$ elements, find the maximum value of the expression:

翻译中…

$$|a_i - a_j| + |a_j - a_k| + |a_k - a_l| + |a_l - a_i|$$

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where $i$, $j$, $k$, and $l$ are four distinct indices of the array $a$, with $1 \le i, j, k, l \le n$.

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Here $|x|$ denotes the absolute value of $x$.

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Input

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The first line contains one integer $t$ ($1 \le t \le 500$) — the number of test cases. The description of the test cases follows.

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The first line of each test case contains a single integer $n$ ($4 \le n \le 100$) — the length of the given array.

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The second line of each test case contains $n$ integers $a_1, a_2, \ldots, a_n$ ($-10^6 \le a_i \le 10^6$).

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Output

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For each test case, print a single integer — the maximum value.

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Note

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In the first test case, for any selection of $i$, $j$, $k$, $l$, the answer will be $0$. For example, $|a_1 - a_2| + |a_2 - a_3| + |a_3 - a_4| + |a_4 - a_1| = |1 - 1| + |1 - 1| + |1 - 1| + |1 - 1| = 0 + 0 + 0 + 0 = 0$.

翻译中…

In the second test case, for $i = 1$, $j = 3$, $k = 2$, and $l = 5$, the answer will be $6$. $|a_1 - a_3| + |a_3 - a_2| + |a_2 - a_5| + |a_5 - a_1| = |1 - 2| + |2 - 1| + |1 - 3| + |3 - 1| = 1 + 1 + 2 + 2 = 6$.

翻译中…

样例

Input #1
5
4
1 1 1 1
5
1 1 2 2 3
8
5 1 3 2 -3 -1 10 3
4
3 3 1 1
4
1 2 2 -1
Output #1
0
6
38
8
8
InputCopy OutputCopy
题目信息
题号
1934A
时间限制
1 s
内存限制
256 MB
标签
贪心
数学

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