Codeforces Round 948 (Div. 2)
B
Binary Colouring
Codeforces
1100
原题
← AC →
翻译中…

You are given a positive integer $x$. Find any array of integers $a_0, a_1, \ldots, a_{n-1}$ for which the following holds:

翻译中…
  • $1 \le n \le 32$,
  • $a_i$ is $1$, $0$, or $-1$ for all $0 \le i \le n - 1$,
  • $x = \displaystyle{\sum_{i=0}^{n - 1}{a_i \cdot 2^i}}$,
  • There does not exist an index $0 \le i \le n - 2$ such that both $a_{i} \neq 0$ and $a_{i + 1} \neq 0$.
翻译中…

It can be proven that under the constraints of the problem, a valid array always exists.

翻译中…

Input

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Each test contains multiple test cases. The first line of input contains a single integer $t$ ($1 \le t \le 10^4$) — the number of test cases. The description of the test cases follows.

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The only line of each test case contains a single positive integer $x$ ($1 \le x \lt 2^{30}$).

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Output

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For each test case, output two lines.

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On the first line, output an integer $n$ ($1 \le n \le 32$) — the length of the array $a_0, a_1, \ldots, a_{n-1}$.

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On the second line, output the array $a_0, a_1, \ldots, a_{n-1}$.

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If there are multiple valid arrays, you can output any of them.

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Note

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In the first test case, one valid array is $[1]$, since $(1) \cdot 2^0 = 1$.

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In the second test case, one possible valid array is $[0,-1,0,0,1]$, since $(0) \cdot 2^0 + (-1) \cdot 2^1 + (0) \cdot 2^2 + (0) \cdot 2^3 + (1) \cdot 2^4 = -2 + 16 = 14$.

翻译中…

样例

Input #1
7
1
14
24
15
27
11
19
Output #1
1
1
5
0 -1 0 0 1
6
0 0 0 -1 0 1
5
-1 0 0 0 1
6
-1 0 -1 0 0 1
5
-1 0 -1 0 1
5
-1 0 1 0 1
InputCopy OutputCopy
题目信息
题号
1977B
时间限制
1 s
内存限制
256 MB
标签
位运算
构造
贪心
数学

题面与样例版权归 Codeforces 及出题人所有;中文翻译由 AI 生成(CI 管线),如有出入请以原文为准。