You are given two numbers $x, y$. You need to determine if there exists an integer $n$ such that $S(n) = x$, $S(n + 1) = y$.
Here, $S(a)$ denotes the sum of the digits of the number $a$ in the decimal numeral system.
Input
Each test contains multiple test cases. The first line contains the number of test cases $t$ ($1 \le t \le 500$). The description of the test cases follows.
The first line of each test case contains two integers $x, y$ ($1 \le x \le 1000, 1 \le y \le 1000$).
Output
For each test case, print "NO" if a suitable $n$ does not exist. Otherwise, output "YES".
You can output each letter in any case (for example, "YES", "Yes", "yes", "yEs", "yEs" will be recognized as a positive answer).
Note
In the first test case, for example, $n = 100$ works. $S(100) = 1$, $S(101) = 2$.
In the second test case, it can be shown that $S(n) \neq S(n+1)$ for all $n$; therefore, the answer is No.
In the fourth test case, $n = 10^{111}-1$ works, which is a number consisting of $111$ digits of $9$.
样例
7
1 2
77 77
997 999
999 1
1000 1
1 11
18 1
Yes
No
No
Yes
No
No
Yes
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