You are given an integer $n$. Find any permutation $p$ of length $n$$^{\text{∗}}$ such that:
- For all
$2 \le i \le n$,$\max(p_{i - 1}, p_i) \bmod i$$^{\text{†}}$$= i - 1$is satisfied.
If it is impossible to find such a permutation $p$, output $-1$.
$^{\text{∗}}$A permutation of length $n$ is an array consisting of $n$ distinct integers from $1$ to $n$ in arbitrary order. For example, $[2,3,1,5,4]$ is a permutation, but $[1,2,2]$ is not a permutation ($2$ appears twice in the array), and $[1,3,4]$ is also not a permutation ($n=3$ but there is $4$ in the array). $^{\text{†}}$$x \bmod y$ denotes the remainder from dividing $x$ by $y$.
Input
Each test contains multiple test cases. The first line contains the number of test cases $t$ ($1 \le t \le 99$). The description of the test cases follows.
The first line of each test case contains a single integer $n$ ($2 \le n \le 100$).
Output
For each test case:
- If such a permutation
$p$doesn't exist, output a single integer$-1$. - Otherwise, output
$n$integers$p_1, p_2, \ldots, p_n$— the permutation$p$you've found. If there are multiple answers, output any of them.
Note
In the first test case, it is impossible to find such a permutation $p$, so you should output $-1$.
In the fourth test case, $p = [1, 5, 2, 3, 4]$ satisfies the condition:
- For
$i = 2$,$\max(p_1, p_2) = 5$and$5 \bmod 2 = 1$. - For
$i = 3$,$\max(p_2, p_3) = 5$and$5 \bmod 3 = 2$. - For
$i = 4$,$\max(p_3, p_4) = 3$and$3 \bmod 4 = 3$. - For
$i = 5$,$\max(p_4, p_5) = 4$and$4 \bmod 5 = 4$.
样例
4
2
3
4
5
-1
3 2 1
-1
1 5 2 3 4
题面与样例版权归 Codeforces 及出题人所有;中文翻译由 AI 生成(CI 管线),如有出入请以原文为准。