In 2077, everything became fashionable among robots, even arrays...

We will call an array of integers $a$ fashionable if $\min(a) + \max(a)$ is divisible by $2$ without a remainder, where $\min(a)$ — the value of the minimum element of the array $a$, and $\max(a)$ — the value of the maximum element of the array $a$.

You are given an array of integers $a_1, a_2, \ldots, a_n$. In one operation, you can remove any element from this array. Your task is to determine the minimum number of operations required to make the array $a$ fashionable.

Input

Each test contains multiple test cases. The first line contains the number of test cases $t$ ($1 \le t \le 10^3$). The description of the test cases follows.

The first line of each test case contains one integer $n$ ($1 \leq n \leq 50$) — the size of the array $a$.

The second line of each test case contains $n$ integers $a_1, a_2, \ldots, a_n$ ($1 \leq a_i \leq 50$) — the elements of the array $a$.

Output

For each test case, output one integer — the minimum number of operations required to make the array $a$ fashionable.

Note

In the first test case, at least one element needs to be removed since $\min(a)+\max(a)=2+5=7$, and $7$ is not divisible by $2$. If any of the elements are removed, only one element will remain. Then $\max(a) + \min(a)$ will be divisible by $2$.

In the second test case, nothing needs to be removed since $\min(a)+\max(a)=1+9=10$, and $10$ is divisible by $2$.

In the third test case, you can remove the elements with values $2$ and $4$, then $\min(a)+\max(a)=5+11=16$, and $16$ is divisible by $2$.