Codeforces Round 164 (Div. 2)
E
Playlist
Codeforces
2100
原题
← D→
翻译中…

Manao's friends often send him new songs. He never listens to them right away. Instead, he compiles them into a playlist. When he feels that his mind is open to new music, he opens the playlist and starts to listen to the songs.

翻译中…

Of course, there are some songs that Manao doesn't particuarly enjoy. To get more pleasure from the received songs, he invented the following procedure of listening to the playlist:

翻译中…
  • If after listening to some song Manao realizes that he liked it, then he remembers it and starts to listen to the next unlistened song.
  • If after listening to some song Manao realizes that he did not like it, he listens to all the songs he liked up to this point and then begins to listen to the next unlistened song.
翻译中…

For example, if Manao has four songs in the playlist, A, B, C, D (in the corresponding order) and he is going to like songs A and C in the end, then the order of listening is the following:

翻译中…
  1. Manao listens to A, he likes it, he remembers it.
  2. Manao listens to B, he does not like it, so he listens to A, again.
  3. Manao listens to C, he likes the song and he remembers it, too.
  4. Manao listens to D, but does not enjoy it and re-listens to songs A and C.
翻译中…

That is, in the end Manao listens to song A three times, to song C twice and songs B and D once. Note that if Manao once liked a song, he will never dislike it on a subsequent listening.

翻译中…

Manao has received $*n*$ songs: the $*i*$-th of them is $*l*_{*i*}$ seconds long and Manao may like it with a probability of $*p*_{*i*}$ percents. The songs could get on Manao's playlist in any order, so Manao wants to know the maximum expected value of the number of seconds after which the listening process will be over, for all possible permutations of the songs in the playlist.

翻译中…

Input

翻译中…

The first line contains a single integer $*n*$ ($1 ≤ *n* ≤ 50000$). The $*i*$-th of the following $*n*$ lines contains two integers, separated by a single space — $*l*_{*i*}$ and $*p*_{*i*}$ ($15 ≤ *l*_{*i*} ≤ 1000$, $0 ≤ *p*_{*i*} ≤ 100$) — the length of the $*i*$-th song in seconds and the probability that Manao will like the song, in percents.

翻译中…

Output

翻译中…

In a single line print a single real number — the maximum expected listening time over all permutations of songs. The answer will be considered valid if the absolute or relative error does not exceed $10^{ - 9}$.

翻译中…

Note

翻译中…

Consider the first test case. If Manao listens to the songs in the order in which they were originally compiled, the mathematical expectation will be equal to 467.5 seconds. The maximum expected value is obtained by putting the first song at the end of the playlist.

翻译中…

Consider the second test case. The song which is 360 seconds long should be listened to first. The song 300 seconds long which Manao will dislike for sure should be put in the end.

翻译中…

样例

Input #1
3
150 20
150 50
100 50
Output #1
537.500000000
InputCopy OutputCopy
Input #2
4
300 0
300 50
240 50
360 80
Output #2
2121.000000000
InputCopy OutputCopy
题目信息
题号
268E
时间限制
1 s
内存限制
256 MB
标签
数学
概率论
排序

题面与样例版权归 Codeforces 及出题人所有;中文翻译由 AI 生成(CI 管线),如有出入请以原文为准。