Codeforces Round 178 (Div. 2)
E
Shaass the Great
Codeforces
2300
原题
← D→
翻译中…

The great Shaass is the new king of the Drakht empire. The empire has $*n*$ cities which are connected by $*n* - 1$ bidirectional roads. Each road has an specific length and connects a pair of cities. There's a unique simple path connecting each pair of cities.

翻译中…

His majesty the great Shaass has decided to tear down one of the roads and build another road with the same length between some pair of cities. He should build such road that it's still possible to travel from each city to any other city. He might build the same road again.

翻译中…

You as his advisor should help him to find a way to make the described action. You should find the way that minimize the total sum of pairwise distances between cities after the action. So calculate the minimum sum.

翻译中…

Input

翻译中…

The first line of the input contains an integer $*n*$ denoting the number of cities in the empire, $(2 ≤ *n* ≤ 5000)$. The next $*n* - 1$ lines each contains three integers $*a*_{*i*}$, $*b*_{*i*}$ and $*w*_{*i*}$ showing that two cities $*a*_{*i*}$ and $*b*_{*i*}$ are connected using a road of length $*w*_{*i*}$, $(1 ≤ *a*_{*i*}, *b*_{*i*} ≤ *n*, *a*_{*i*} ≠ *b*_{*i*}, 1 ≤ *w*_{*i*} ≤ 10^{6})$.

翻译中…

Output

翻译中…

On the only line of the output print the minimum pairwise sum of distances between the cities.

翻译中…

Please do not use the %lld specificator to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams or the %I64d specificator.

翻译中…

样例

Input #1
3
1 2 2
1 3 4
Output #1
12
InputCopy OutputCopy
Input #2
6
1 2 1
2 3 1
3 4 1
4 5 1
5 6 1
Output #2
29
InputCopy OutputCopy
Input #3
6
1 3 1
2 3 1
3 4 100
4 5 2
4 6 1
Output #3
825
InputCopy OutputCopy
题目信息
题号
294E
时间限制
3.5 s
内存限制
256 MB
标签
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题面与样例版权归 Codeforces 及出题人所有;中文翻译由 AI 生成(CI 管线),如有出入请以原文为准。