Codeforces Round 201 (Div. 2)
B
Fixed Points
Codeforces
1100
原题
← AC →
翻译中…

A permutation of length $*n*$ is an integer sequence such that each integer from 0 to $(*n* - 1)$ appears exactly once in it. For example, sequence $[0, 2, 1]$ is a permutation of length 3 while both $[0, 2, 2]$ and $[1, 2, 3]$ are not.

翻译中…

A fixed point of a function is a point that is mapped to itself by the function. A permutation can be regarded as a bijective function. We'll get a definition of a fixed point in a permutation. An integer $*i*$ is a fixed point of permutation $*a*_{0}, *a*_{1}, ..., *a*_{*n* - 1}$ if and only if $*a*_{*i*} = *i*$. For example, permutation $[0, 2, 1]$ has $1$ fixed point and permutation $[0, 1, 2]$ has $3$ fixed points.

翻译中…

You are given permutation $*a*$. You are allowed to swap two elements of the permutation at most once. Your task is to maximize the number of fixed points in the resulting permutation. Note that you are allowed to make at most one swap operation.

翻译中…

Input

翻译中…

The first line contains a single integer $*n*$ $(1 ≤ *n* ≤ 10^{5})$. The second line contains $*n*$ integers $*a*_{0}, *a*_{1}, ..., *a*_{*n* - 1}$ — the given permutation.

翻译中…

Output

翻译中…

Print a single integer — the maximum possible number of fixed points in the permutation after at most one swap operation.

翻译中…

样例

Input #1
5
0 1 3 4 2
Output #1
3
InputCopy OutputCopy
题目信息
题号
347B
时间限制
2 s
内存限制
256 MB
标签
暴力
模拟
数学

题面与样例版权归 Codeforces 及出题人所有;中文翻译由 AI 生成(CI 管线),如有出入请以原文为准。