Codeforces Round 221 (Div. 1)
E
Red and Black Tree
Codeforces
3000
原题
← D→
翻译中…

You have a weighted tree, consisting of $*n*$ vertices. Each vertex is either painted black or is painted red. A red and black tree is called beautiful, if for any its vertex we can find a black vertex at distance at most $*x*$.

翻译中…

The distance between two nodes is the shortest path between them.

翻译中…

You have a red and black tree. Your task is to make it beautiful in the minimum number of color swap operations. In one color swap operation, you can choose two vertices of different colors and paint each of them the other color. In other words, if you choose a red vertex $*p*$ and a black vertex $*q*$, then in one operation you are allowed to paint $*p*$ black and paint $*q*$ red.

翻译中…

Print the minimum number of required actions.

翻译中…

Input

翻译中…

The first line contains two integers $*n*$ and $*x*$ $(2 ≤ *n* ≤ 500; 1 ≤ *x* ≤ 10^{9})$. The next line contains $*n*$ integers, each of them is either a zero or one. If the $*i*$-th number equals 1, then vertex $*i*$ of the tree is black, otherwise vertex $*i*$ is red. Next $*n* - 1$ lines contain the tree edges. The $*j*$-th line contains integers $*u*_{*j*} *v*_{*j*} *w*_{*j*}$ $(1 ≤ *u*_{*j*}, *v*_{*j*} ≤ *n*; *u*_{*j*} ≠ *v*_{*j*}; 1 ≤ *w*_{*j*} ≤ 10^{9})$ which means that the tree has an edge of weight $*w*_{*j*}$ between vertices $*v*_{*j*}$ and $*u*_{*j*}$.

翻译中…

Assume that the tree vertices are numbered from 1 to $*n*$.

翻译中…

Output

翻译中…

Print a single integer — the minimum number of required swap operations.

翻译中…

If it is impossible to get a beautiful tree at any number of operations, print -1.

翻译中…

样例

Input #1
3 2
1 0 0
1 2 2
2 3 2
Output #1
1
InputCopy OutputCopy
Input #2
4 2
0 1 0 0
1 2 2
2 3 2
3 4 2
Output #2
-1
InputCopy OutputCopy
题目信息
题号
375E
时间限制
1 s
内存限制
256 MB
标签
动态规划
模拟
数学

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