Coder-Strike 2014 - Round 2
D
2048
Codeforces
2000
原题
← CE →
翻译中…

The programmers from the R2 company love playing 2048. One day, they decided to invent their own simplified version of this game — $2^{*k*}$ on a stripe.

翻译中…

Imagine an infinite in one direction stripe, consisting of unit squares (the side of each square is equal to the height of the stripe). Each square can either be empty or contain some number.

翻译中…

Initially, all squares are empty. Then at infinity one of the unit squares number 2 or 4 appears. Then the player presses a button once, and the appeared number begins to move towards the beginning of the stripe. Let's assume that some number $*x*$ moves to the beginning of the stripe, then it will stop if:

翻译中…
  1. it either gets in the first square of the stripe;
  2. or it is in the square that is preceded by a square with number $*y*$ $(*y* ≠ *x*)$. But if number $*x*$ at some point of time gets to the square with the same number then both numbers add to each other and result in $2*x*$. The new number $2*x*$ continues moving to the beginning of the stripe by the same rules.
翻译中…

After the final stop of the number moving process, the infinity gets a new number 2 or 4 and the process repeats. Read the notes to the test samples to better understand the moving strategy.

翻译中…

I guess you've understood that the game progress fully depends on the order in which numbers 2 and 4 appear. Let's look at some sequence of numbers 2 and 4 in the game. We assume that the sequence is winning if it results in at least one square getting the number greater or equal than $2^{*k*}$.

翻译中…

The goal of the game is to make up a winning sequence of $*n*$ numbers. But not everything is so simple, some numbers in the sequence are identified beforehand. You are given a sequence consisting of numbers 0, 2, 4. Count how many ways there are to replace each 0 of the sequence with 2 or 4 to get a winning sequence.

翻译中…

Input

翻译中…

The first line contains two integers $*n*$ and $*k*$ $(1 ≤ *n* ≤ 2000; 3 ≤ *k* ≤ 11)$. The next line contains sequence of $*n*$ integers, each of them is either 0, or 2, or 4.

翻译中…

Output

翻译中…

Print a single integer — the number of ways to replace zeroes by numbers 2 or 4 to get a winning sequence. As this number can be rather large, print it modulo $1000000007$ $(10^{9} + 7)$.

翻译中…

Note

翻译中…

Consider the first example. The beginning of the strip will look as follows:

翻译中…

2 $→$ 4 $→$ 8 $→$ 8 2 $→$ 8 4 $→$ 8 4 2 $→$ 16.

翻译中…

To better understand the game, you can see the original game on http://gabrielecirulli.github.io/2048/. Please note that the game that is described on the strip is slightly different from the original game (when the two numbers add up in the original game, they do not keep moving). Be careful, the game is addictive, there isn't much time for the contest!

翻译中…

样例

Input #1
7 4
2 2 4 2 2 2 2
Output #1
1
InputCopy OutputCopy
Input #2
1 3
0
Output #2
0
InputCopy OutputCopy
Input #3
2 3
0 4
Output #3
1
InputCopy OutputCopy
Input #4
5 4
2 0 0 4 4
Output #4
2
InputCopy OutputCopy
题目信息
题号
413D
时间限制
1 s
内存限制
256 MB
标签
位运算
动态规划

题面与样例版权归 Codeforces 及出题人所有;中文翻译由 AI 生成(CI 管线),如有出入请以原文为准。