DZY loves Fast Fourier Transformation, and he enjoys using it.
Fast Fourier Transformation is an algorithm used to calculate convolution. Specifically, if $*a*$, $*b*$ and $*c*$ are sequences with length $*n*$, which are indexed from $0$ to $*n* - 1$, and

We can calculate $*c*$ fast using Fast Fourier Transformation.
DZY made a little change on this formula. Now

To make things easier, $*a*$ is a permutation of integers from $1$ to $*n*$, and $*b*$ is a sequence only containing $0$ and $1$. Given $*a*$ and $*b*$, DZY needs your help to calculate $*c*$.
Because he is naughty, DZY provides a special way to get $*a*$ and $*b*$. What you need is only three integers $*n*$, $*d*$, $*x*$. After getting them, use the code below to generate $*a*$ and $*b*$.
//x is 64-bit variable;
function getNextX() {
x = (x * 37 + 10007) % 1000000007;
return x;
}
function initAB() {
for(i = 0; i < n; i = i + 1){
a[i] = i + 1;
}
for(i = 0; i < n; i = i + 1){
swap(a[i], a[getNextX() % (i + 1)]);
}
for(i = 0; i < n; i = i + 1){
if (i < d)
b[i] = 1;
else
b[i] = 0;
}
for(i = 0; i < n; i = i + 1){
swap(b[i], b[getNextX() % (i + 1)]);
}
}
Operation x % y denotes remainder after division $*x*$ by $*y*$. Function swap(x, y) swaps two values $*x*$ and $*y*$.
Input
The only line of input contains three space-separated integers $*n*, *d*, *x* (1 ≤ *d* ≤ *n* ≤ 100000; 0 ≤ *x* ≤ 1000000006)$. Because DZY is naughty, $*x*$ can't be equal to $27777500$.
Output
Output $*n*$ lines, the $*i*$-th line should contain an integer $*c*_{*i* - 1}$.
Note
In the first sample, $*a*$ is $[1 3 2]$, $*b*$ is $[1 0 0]$, so $*c*_{0} = *max*(1·1) = 1$, $*c*_{1} = *max*(1·0, 3·1) = 3$, $*c*_{2} = *max*(1·0, 3·0, 2·1) = 2$.
In the second sample, $*a*$ is $[2 1 4 5 3]$, $*b*$ is $[1 1 1 0 1]$.
In the third sample, $*a*$ is $[5 2 1 4 3]$, $*b*$ is $[1 1 1 1 0]$.
样例
3 1 1
1
3
2
5 4 2
2
2
4
5
5
5 4 3
5
5
5
5
4
题面与样例版权归 Codeforces 及出题人所有;中文翻译由 AI 生成(CI 管线),如有出入请以原文为准。